
now
standard form for a linear equation means
• all coefficients must be integers, no fractions
• only the constant on the right-hand-side
• all variables on the left-hand-side, sorted
• "x" must not have a negative coefficient
therefore,

Since
it follows that
is a root of multiplicity 2.
Answer:
3
Step-by-step explanation:
because 3 is a prime number and 3+2=5 which is also a prime number
Answer:
wow this your first Q
Step-by-step explanation:
B is the answer when the parabola is facing down it is negative