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2 years ago

5

What is the x-intercept of the line 5x+2y=10

2 answers:

inessss [21]2 years ago

8 0

5x is the x-intercept.

Eddi Din [679]2 years ago

6 0

The x-intercept of the line 5x+2y=10
(2,0)

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The weight of a radioactive isotope was 96 grams at the start of an experiment. After one hour, the weight of the isotope was ha

zimovet [89]

The starting weight of the radioactive isotope = 96 grams

Weight after one hour is half of the starting weight. So the weight of the radioactive isotope after 1 hour = 48 grams

After 2 hours the weight is half as compared to the weight after previous hour. So weight after 2 hours = 24 grams.

This means, after every hour the weight is being halved. The half life of radioactive isotope is one hour.

Since after every hour, the weight is being halved, the weight of the isotope can be modeled by an exponential equation.

So,

Initial Weight = W₁ = 96
Change factor = 1/2 = 0.5

The general equation of the sequence will be:

$\\ \\ W_{t}=96(0.5)^{t}$

Here t represents the number of hours. Using various values of t we can find the weight of the radioactive isotope at that time.

We can plot the sequence using the above equation. The graph is attached below.

3 0

2 years ago

Read 2 more answers

Suppose line segment AB has one endpoint at A(0, 0). What are the coordinates of B if (5, 3) is 1/3 of the way from A to B?

prisoha [69]

Answer:

$B(x_2,y_2)= (20,12)$

Step-by-step explanation:

Given

$A = (0,0)$

$Ratio; m : n = 1 : 3$

$Point\ at\ 1 : 3 = (5,3)$

Required

Coordinates of B

This question will be answered using line ratio formula;

$(x,y) = (\frac{mx_2 + nx_1}{m + n},\frac{my_2 + ny_1}{m + n})$

In this case:

$(x,y) = (5,3)$

$(x_1,y_1) = (0,0)$

$m : n = 1 : 3$

Solving for $(x_2,y_2)$

$(x,y) = (\frac{mx_2 + nx_1}{m + n},\frac{my_2 + ny_1}{m + n})$ becomes

$(5,3) = (\frac{1 * x_2 + 3 * 0}{1 + 3},\frac{1 * y_2 + 3 * 0}{1 + 3})$

$(5,3) = (\frac{x_2 + 0}{4},\frac{y_2 + 0}{4})$

$(5,3) = (\frac{x_2}{4},\frac{y_2}{4})$

Comparing the right hand side to the left;

$\frac{x_2}{4} = 5$ -- (1)

$\frac{y_2}{4} = 3$ -- (2)

Solving (1)

$x_2 = 5 * 4$

$x_2 = 20$

Solving (2)

$y_2 = 3 * 4$

$y_2 = 12$

Hence;

$B(x_2,y_2)= (20,12)$

5 0

3 years ago

Find an ordered triple that represents 65 = (2, 6, 8) and Ž = (1, -2, 6).

Igoryamba

Answer:

< 40, 28, 72 >

Step-by-step explanation:

Given

y = < 2, 6, 8 > and z = < 7, - 2, 6 > , then

6y + 4z

= 6 < 2, 6, 8 > + 4 < 7, - 2, 6 >

Multiply each component by the scalar quantity

= < 6(2), 6(6), 6(8) > + < 4(7), 4(- 2), 4(6) >

= < 12, 36, 48 > + < 28, - 8, 24 >

Add corresponding components

= < 12 + 28, 36 - 8, 48 + 24 >

= < 40, 28, 72 >

4 0

3 years ago

which of the following is a lab hazard A. laser radiation hazard B. animal hazard C. Explosive hazard D. chemical

QveST [7]

Answer:

c maybe

Step-by-step explanation:

4 0

2 years ago

Read 2 more answers

Suppose that the functions g and h are defined for all real numbers r as follows. gx) -4x +5 h (x) = 6x write the expressions fo

aleksandr82 [10.1K]

Answer: Our required values would be -10x+5, 2x+5 and -25.

Step-by-step explanation:

Since we have given that

g(x) = -4x+5

and

h(x) = 6x

We need to find (g-h)(x) and (g+h)(x).

So, (g-h)(x) is given by

$g(x)-h(x)\\\\=-4x+5-6x\\\\=-10x+5$

and (g+h)(x) is given by

$g(x)+h(x)\\\\=-4x+5+6x\\\\=2x+5$

and (g-h)(3) is given by

$-10(3)+5\\\\=-30+5\\\\=-25$

Hence, our required values would be -10x+5, 2x+5 and -25.

5 0

3 years ago