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Ivanshal [37]
2 years ago
14

What is the value of x in the equation 2x + 3y=36,when y=6​

Mathematics
1 answer:
levacccp [35]2 years ago
4 0

Answer: x=9

Step-by-step explanation: rewrite the given equation with y=6, 2x + 3(6)=36

Now simplify 2x +18=36

Subtract 18 from both sides of the equal

2x=18

Now divide both sides by 2 and your answer is x=9

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The stock market dropped 220 points on Monday. It lost another 48 points on Tuesday, and on Wednesday, it gained 96 points. What
MissTica

48 points gained in those 3 days.

Subtract 220 with 48, then add 96. Last step would be subtracting 220 with the amount they have now in those 3 days to find how much points the stock market gained in those 3 days.

Subtract 220-48.It‘ll be 172.

Add 172 with 96. 172+96=268.

Subtract 268 with how much points the stock market had 3 days ago. 268-220.

Sot eh stock market gained 48 points in 3 days.

4 0
3 years ago
Does this graph represent a function? Why or why not? Sey A. No, because it fails the vertical line test. B. Yes, because it has
Fittoniya [83]

Answer: it’s A..

Step-by-step explanation:

No, because it fails the vertical line test.

7 0
3 years ago
Please I need help with differential equation. Thank you
Inga [223]

1. I suppose the ODE is supposed to be

\mathrm dt\dfrac{y+y^{1/2}}{1-t}=\mathrm dy(t+1)

Solving for \dfrac{\mathrm dy}{\mathrm dt} gives

\dfrac{\mathrm dy}{\mathrm dt}=\dfrac{y+y^{1/2}}{1-t^2}

which is undefined when t=\pm1. The interval of validity depends on what your initial value is. In this case, it's t=-\dfrac12, so the largest interval on which a solution can exist is -1\le t\le1.

2. Separating the variables gives

\dfrac{\mathrm dy}{y+y^{1/2}}=\dfrac{\mathrm dt}{1-t^2}

Integrate both sides. On the left, we have

\displaystyle\int\frac{\mathrm dy}{y^{1/2}(y^{1/2}+1)}=2\int\frac{\mathrm dz}{z+1}

where we substituted z=y^{1/2} - or z^2=y - and 2z\,\mathrm dz=\mathrm dy - or \mathrm dz=\dfrac{\mathrm dy}{2y^{1/2}}.

\displaystyle\int\frac{\mathrm dy}{y^{1/2}(y^{1/2}+1)}=2\ln|z+1|=2\ln(y^{1/2}+1)

On the right, we have

\dfrac1{1-t^2}=\dfrac12\left(\dfrac1{1-t}+\dfrac1{1+t}\right)

\displaystyle\int\frac{\mathrm dt}{1-t^2}=\dfrac12(\ln|1-t|+\ln|1+t|)+C=\ln(1-t^2)^{1/2}+C

So

2\ln(y^{1/2}+1)=\ln(1-t^2)^{1/2}+C

\ln(y^{1/2}+1)=\dfrac12\ln(1-t^2)^{1/2}+C

y^{1/2}+1=e^{\ln(1-t^2)^{1/4}+C}

y^{1/2}=C(1-t^2)^{1/4}-1

I'll leave the solution in this form for now to make solving for C easier. Given that y\left(-\dfrac12\right)=1, we get

1^{1/2}=C\left(1-\left(-\dfrac12\right)^2\right))^{1/4}-1

2=C\left(\dfrac54\right)^{1/4}

C=2\left(\dfrac45\right)^{1/4}

and so our solution is

\boxed{y(t)=\left(2\left(\dfrac45-\dfrac45t^2\right)^{1/4}-1\right)^2}

3 0
3 years ago
What is 57 divided by 3591
lbvjy [14]
57/ 3591
= (57/57) / (3591/57)
= 1/63

The final answer is 1/63~
7 0
3 years ago
a theory states that the cpu clock speed in a computer doubles every 18 months. if the clock speed was 33 MHz in 1991, how can y
Marina CMI [18]
The simple way to double something more than once is to multiply the original number by 2 and then double the product until the final amount of doubles has been reached, in this case, 3. Doubling 33 3 times, we get 264
7 0
3 years ago
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