Answer:
d
Explanation:
Eternity because it could be culprited by the True Anomaly and the Argument of perigee
Answer:
Combination circuit; The basic strategy for the analysis of combination circuits involves using the meaning of equivalent resistance for parallel branches to transform the combination circuit into a series circuit.
Example:
The use of both series and parallel connections within the same circuit. In this case, light bulbs A and B are connected by parallel connections and light bulbs C and D are connected by series connections. This is an example of a combination circuit.
Answer:
12 N-m
Explanation:
The dc motor is operating at 24 V that is its terminal voltage V =24 V
Armature resistance = 0.2 ohm
No load speed = 240 radian /sec
For motor we know that as the motor is on no load so so
Power developed in the motor
Now we know that power = torque× angular speed
So
Answer:
Volume of face centered cubic cell=
Explanation:
Consider the face centered cubic cell:
1 atom at each corner of cube.
1 atom at center of each face.
Consider the one face (ABCD) as shown in attachment for calculation:
Length of the all sides of face centered cubic cell is L.
Volume of face centered cubic cell= L^3
Now Consider the figure shown in attachment:
According to Pythagoras theorem on ΔADC.
(a is the atomic radius)
(Put in the formula of Volume)
Volume of face centered cubic cell= L^3
Volume of face centered cubic cell= 
Volume of face centered cubic cell= 
Volume of face centered cubic cell=
Answer:
The solution is written in Python
- binary = ""
- decimal = 13
- quotient = int(decimal / 2)
- remainder = decimal % 2
- binary = str(remainder) + binary
-
- while(quotient >0):
- decimal = int(decimal / 2)
- quotient = int(decimal / 2)
- remainder = decimal % 2
- binary = str(remainder) + binary
-
- print(binary)
Explanation:
Firstly, we declare a variable <em>binary</em> and initialize it with an empty string (Line 1). This <em>binary </em>is to hold the binary string.
Next, we declare variable <em>decimal, quotient </em>and<em> remainder </em>(Line 2-4). We assign a test value 13 to decimal variable and then get the first quotient by dividing decimal with 2 (Line 3). Then we get the remainder by using modulus operator, % (Line 4). The first remainder will be the first digit joined with the binary string (Line 5).
We need to repeat the process from Line 3-5 to get the following binary digits. Therefore create a while loop (Line 7) and set a condition that if quotient is bigger than 0 we keep dividing decimal by 2 and calculate the quotient and remainder and use the remainder as a binary digit and join it with binary string from the front (Line 9-11).
At last, we print the binary to terminal (Line 13).
