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Vedmedyk [2.9K]
4 years ago
15

If the atomic radius of copper is 0.128 nm, calculate the volume of its unit cell in cubic meters.

Engineering
1 answer:
Alex_Xolod [135]4 years ago
3 0

Answer:

Volume of face centered cubic cell=4.74531*10^{-29} m^3

Explanation:

Consider the face centered cubic cell:

1 atom at each corner of cube.

1 atom at center of each face.

Consider the one face (ABCD) as shown in attachment for calculation:

Length of the all sides of face centered cubic cell is L.

Volume of face centered cubic cell= L^3

Now Consider the figure shown in attachment:

According to Pythagoras theorem on ΔADC.

L^{2}+L^2=(4a)^2     (a is the atomic radius)

L=\frac{4a}{\sqrt{2}} (Put in the formula of Volume)

Volume of face centered cubic cell= L^3

Volume of face centered cubic cell= (\frac{4a}{\sqrt{2}})^3

Volume of face centered cubic cell= (\frac{4(0.128*10^{-9}}{\sqrt{2}})^3

Volume of face centered cubic cell=4.74531*10^{-29} m^3

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When a man returns to his well-sealed house on a summer day, he finds that the house is at 35°C. He turns on the air conditioner
ipn [44]

Answer:

\dot W = 1.667\, kW

Explanation:

A well-sealed house means that there is no mass interaction between air indoors and outdoors. Hence, cooling process is isochoric. The heat removed by the air conditioner is:

\dot Q_{L} = \frac{m_{air}}{\Delta t} \cdot c_{v, air} \cdot (T_{o}-T_{f})\\\dot Q_{L} = \frac{800\, kg}{(30\, min)\cdot (\frac{60\, s}{1 \, min} )}\cdot (0.7 \frac{kJ}{kg \cdot K}) \cdot (15\, K)\\\dot Q_{L} = 4.667\, kW

The power drawn by the air conditioner is:

\dot W = \frac{\dot Q_{L}}{COP_{R}} \\\dot W = \frac {4.667\, kW}{2.8}\\\dot W = 1.667\, kW

3 0
3 years ago
An uncovered swimming pool loses 1.0 inch of water off its 1,000 ft^2 surface each week due to evaporation. The heat of vaporiza
soldi70 [24.7K]

Answer:

The affirmation is true, the cover will be worth buying

Explanation:

The equation necessary to use is

E = m*cv,

Where

cv: the heat of vaporization.  

Finding the rate at which the water evaporates (m^3/week).  

The swimming pool loses water at 1 inch/week off its 1,000 ft^2

Than,

1000 ft² * 1 in/wk * 1 ft/12 in = 83.33 ft³/week

To obtains the rate of mass loss it is necessary to multiply it for the density of water

83.33 ft³/week * 62.4 lb/ft³ = 5200 lb/week

Knowing the vaporization heat it is possible to find the rate of heat which is leaving the swimming pool  

5200 lb/week * 1050 BTU/lb = 5460000 btu/week

Over a 15-week period, the pool loses 81.9 million BTU.  

Knowing the cost of energy to heat the pool is $10.00 per million btu

The price = $819

This way, the affirmation is true, the cover will be worth buying

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3 years ago
Why is transverse unequal length wishbone preferred to that of equal length?
Damm [24]

Answer:

It allows the wheels to move of the neutral position without the tires scrubbing

Explanation:

The double wishbone suspension is independent and it can be used in both the front wheels and it affords very good control of the outward or inward tilting of the front wheel and it keeps the wheels perpendicular to the road surface

However, when equal length parallel wishbone are installed, it gives rise to scrubbing of the tires as the wheels turn in the tracks

The development of unequal length non-parallel transverse or converging wishbones with A-arms suspension resolved the tire scrubbing effect on the wheels when moving out of the neutral position.

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4 years ago
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My day as been going awesome
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A steady, incompressible, two-dimensional velocity field is given by the following components in the x-y plane: u=1.85+2.05x+0.6
AnnZ [28]

Answer:

\frac{du}{dt} = 1.515

\frac{dv}{dt} = 5.511

Explanation:

The acceleration field is obtained by deriving the components in function of the time. That is to say:

\frac{du}{dt}=2.05\cdot \frac{dx}{dt}+0.656\cdot \frac{dy}{dt}\\\frac{dv}{dt} = -2.18\cdot \frac{dx}{dt} -2.05\cdot \frac{dy}{dt}

Where \frac{dx}{dt} = u and \frac{dy}{dt} = v.

The velocity components at given point are, respectively:

u = 2.424

v=-5.266

Lastly, the acceleration components are found:

\frac{du}{dt} = 1.515

\frac{dv}{dt} = 5.511

7 0
3 years ago
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