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siniylev [52]
3 years ago
15

Carlton is solving a linear equation using the steps shown.

Mathematics
2 answers:
Alja [10]3 years ago
6 0

Step-by-step explanation:

The next step is

12 = - 2x

12 / - 2 = x

-6 = x

Andrei [34K]3 years ago
5 0

Answer:

d i took the test

Step-by-step explanation:

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Which statements about the graph of the function y=(1/3)
Elena-2011 [213]
Answer: The range of the function is all real numbers is true.

Explanation: the graph of y = 1/3 is just a horizontal line at y = 1/3. so it’s not increasing or decreasing (it’s staying the same). there is no x-intercept, and the y-intercept is (0, 1/3). the range is all the possible y values, and there are infinite possible y values, so it is all real numbers.

hope this helps!
8 0
3 years ago
Choose values for n and graph. f(n) = n to the second power + (-2)
Rus_ich [418]
No clue what the answer is I am not that good I am blonde
now goodbye
5 0
3 years ago
The corners of a meadow are shown on a coordinate grid. Ethan wants to fence the meadow. What length of fencing is required?
Nuetrik [128]

Answer:

34.6 units

Step-by-step explanation:

The lenght of fencing required is the total distance between point A to B, B to C, C to D, and D to A. That is the distance between all 4 corners of the meadow.

The coordinates of the corners of the meadow is shown on a coordinate plane in the attachment. (See attachment below).

Let's use the distance formula to calculate the distance between the 4 corners of the meadow using their coordinates as follows:

Distance between point A(-6, 2) and point B(2, 6):

AB = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}

Let,

A(-6, 2)) = (x_1, y_1)

B(2, 6) = (x_2, y_2)

AB = \sqrt{(2 - (-6))^2 + (6 - 2)^2}

AB = \sqrt{(8)^2 + (4)^2}

AB = \sqrt{64 + 16} = \sqrt{80}

AB = 8.9 (nearest tenth)

Distance between B(2, 6) and C(7, 1):

BC = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}

Let,

B(2, 6) = (x_1, y_1)

C(7, 1) = (x_2, y_2)

BC = \sqrt{(7 - 2)^2 + (1 - 6)^2}

BC = \sqrt{(5)^2 + (-5)^2}

BC = \sqrt{25 + 25} = \sqrt{50}

BC = 7.1 (nearest tenth)

Distance between C(7, 1) and D(3, -5):

CD = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}

Let,

C(7, 1) = (x_1, y_1)

D(3, -5) = (x_2, y_2)

CD = \sqrt{(3 - 7)^2 + (-5 - 1)^2}

CD = \sqrt{(-4)^2 + (-6)^2}

CD = \sqrt{16 + 36} = \sqrt{52}

CD = 7.2 (nearest tenth)

Distance between D(3, -5) and A(-6, 2):

DA = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}

Let,

D(3, -5) = (x_1, y_1)

A(-6, 2) = (x_2, y_2)

DA = \sqrt{(-6 - 3)^2 + (2 - (-5))^2}

DA = \sqrt{(-9)^2 + (7)^2}

DA = \sqrt{81 + 49} = \sqrt{130}

DA = 11.4 (nearest tenth)

Length of fencing required = 8.9 + 7.1 + 7.2 + 11.4 = 34.6 units

8 0
2 years ago
X^3 + 3x^2 -10x factor polynomial and find zero​
Fantom [35]

Answer:

  1. x(x - 2)(x + 5)
  2. x = 0, x = 2, x = -5

Step-by-step explanation:

x^3 + 3x^2 - 10x

~Factor

x(x - 2)(x + 5)

Solve for the zero.

x(x - 2)(x + 5) = 0

We know that; x = 0, x - 2 = 0, and x + 5 = 0

x = 0

x - 2 = 0

x = 2

x + 5 = 0

x = -5

Best of Luck!

7 0
2 years ago
Read 2 more answers
Please help answer this question!
allochka39001 [22]

Answer:

The answer will be 8.38709677419

3 0
2 years ago
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