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siniylev [52]
4 years ago
15

Carlton is solving a linear equation using the steps shown.

Mathematics
2 answers:
Alja [10]4 years ago
6 0

Step-by-step explanation:

The next step is

12 = - 2x

12 / - 2 = x

-6 = x

Andrei [34K]4 years ago
5 0

Answer:

d i took the test

Step-by-step explanation:

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20% of what number is 479<br> 168<br> 0 235<br> O230<br> 094
Temka [501]

Answer:

168 hope  this is right

Step-by-step explanation:

3 0
3 years ago
Please answer this correctly
prohojiy [21]

Answer:

Hi there!

The answer to the answer to this question is: 1,399.286

Step-by-step explanation:

There is two methods you can solve this question, either with long division or short division in this case I chose short division and got 1,399.286

6 0
4 years ago
If I fall for 18 s what would my final velocity be, if I started from rest.
ozzi

Answer:

176.58 m/s

Step-by-step explanation:

assume that the acceleration due to gravity, g = 9.81 m/s²

I also assume we neglect air resistance (hence we assume no terminal velocity)

recall that one of the equations of motions can be expressed as

v = u + at, where

u = initial velocity = 0 (because it says you started from rest)

v = final velocity (we are asked to find this)

a = acceleration due to gravity = 9.81 m/s²

t = time = given as 18s

simply substitute the above into the equation.

v = 0 + (9.81)(18)

v = 176.58 m/s

8 0
3 years ago
a tree struck by lightning broke at a point 12 ft above the ground. what was the height of the tree to the nearest tenth of a fo
mart [117]
Ten foot is the answer ....








3 0
4 years ago
Find the exact value
ivann1987 [24]

Answer:

A

Step-by-step explanation:

cos~ \theta=\sqrt{1-sin^2 \theta} =\sqrt{1-(\frac{1}{2})^2 } =\frac{\sqrt{3} }{2} \\1+cos~\theta=2cos^2\frac{\theta}{2} \\1+\frac{\sqrt{3}}{2} =2~cos^2 \frac{\theta}{2} \\cos^2\frac{\theta}{2} =\frac{2+\sqrt{3}}{2 \times 2} \\cos \frac{\theta}{2} =\frac{\sqrt{2+\sqrt{3}}}{2} \\1-cos \theta=2 ~sin^2\frac{\theta}{2} \\1-\frac{\sqrt{3}}{2}=2~sin^2 \frac{\theta}{2} \\sin^2 \frac{\theta}{2} =\frac{2-\sqrt{3} }{2 \times 2} \\sin \frac{\theta}{2}=\frac{\sqrt{2-\sqrt{3} } }{2}

as 0≤θ≤90

so θ/2 is also in 0≤θ≤90

hence sin θ/2 and cos θ/2 are positive.

3 0
3 years ago
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