Ok, first we need to organize. <span>14, 8, 23, 9, 11, 27, 22, 3, 17, 12, 29 </span>3, 8, 9, 11, 12, 14, 17, 22, 23, 27, 29.
First, we need to find the median, the or the middle, which is 14. Now that we know the median is fourteen, we take away all numbers to the left of 14, including 14: 17, 22, 23, 27, 29. Now just find the median in this new set of numbers. This will give us our upper quartile, which is 23. Hope this helped, and don't forget to drop a like.
First of all, Rodger must be making some serious cash to have 47 cars. Going back to the question, he can not group the cars in more than 2 ways. He can only group it in 1 way, 47 groups of 1. Pls brainliest
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To solve this problem, we are going to use trial and error. If the 2 numbers are 3 and 4 then 3 and 4 is 12 and 3 + 4 = 7 which cannot be divided equally, so this is not the answer. 3 and 5 = 15 but this is not divisible by 2. 6 and 3 = 18 and 6 + 3 = 9 which is 1/2 of 18 therefore, one set is 6 and 3.
Since three angles of one triangle are congruent to three corresponding angles of the other triangle, the triangles are either congruent or similar. Since the side of one triangle is twice the length of the corresponding side of the other triangle, then the triangles are not congruent, but they are similar.
