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3 years ago

The upper quartile for the data set given below is. 14, 8, 23, 9, 11, 27, 22, 3, 17, 12, 29

1 answer:

5 0

Ok, first we need to organize.
14, 8, 23, 9, 11, 27, 22, 3, 17, 12, 29
3, 8, 9, 11, 12, 14, 17, 22, 23, 27, 29.

First, we need to find the median, the or the middle, which is 14.
Now that we know the median is fourteen, we take away all numbers to the left of 14, including 14: 17, 22, 23, 27, 29. Now just find the median in this new set of numbers. This will give us our upper quartile, which is 23. Hope this helped, and don't forget to drop a like.

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Given f(x)=12x−5, find f(4). To earn full credit, show your work using a method explained in the Orientation.

Anvisha [2.4K]

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2 years ago

Given that 2/3a = 16, which of the following illustrates how the multiplicative inverse

harkovskaia [24]

Since the multiplicative inverse of a fraction p/q is the fraction that swaps its numerator and denominator, i.e. q/p, we have that the inverse of 2/3 is 3/2.

So, if we multiply both sides of the equation by 3/2, we have

$\dfrac{3}{2}\cdot\dfrac{2}{3}a=16\cdot\dfrac{3}{2}$

3/2 and 2/3 are multiplicative inverse of each other, and by definition this means that they give 1 when multiplied:

$\dfrac{3}{2}\cdot\dfrac{2}{3}a=1\cdot a=a=16\cdot\dfrac{3}{2}$

On the right hand side, we have

$16\cdot\dfrac{3}{2}=8\cdot 3=24$

And so the solution is $a=24$

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2 years ago