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2 years ago

(a) Find the slope of the line through (-9, -7) and (-19. -47).

Mathematics

2 answers:

wariber [46]2 years ago

5 0

Y2-y1/x2-x1= -47-(-7)/-19-(-9)= 4

Marta_Voda [28]2 years ago

3 0

Answer:

Step-by-step explanation:

The equation for slope is:

$Slope = \frac{y_2-y_1}{x_2-x_1}$

We can plug in the given points into the equation:

$Slope = \frac{-47-(-7)}{-19-(-9)}=\frac{-47+7}{-19+9}=\frac{-40}{-10}=4$

The slope is 4

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d.9

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c) For this case we have the sample size n = 25 and the sample variance is $s^2 =400$ , the standard error can founded with this formula:

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Step-by-step explanation:

Part a

For the first part we have a sample of n =10 and we want to find the degrees of freedom, and we can use the following formula:

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Part b

From a sample we know that n=41 and SS= 600, where SS represent the sum of quares given by:

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$s^2 = \frac{SS}{n-1}= \frac{600}{41-1}= 15$

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Part c

For this case we have the sample size n = 25 and the sample variance is $s^2 =400$ , the standard error can founded with this formula:

$SE = \frac{s^2}{\sqrt{n}}= \frac{400}{\sqrt{25}}= 80$

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