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MariettaO [177]
3 years ago
10

What is the slope of this graph? A. −14 B. 4 C.−4 D. 14

Mathematics
2 answers:
DiKsa [7]3 years ago
6 0
What graph are you talking about:? can you give a pivture
Anna007 [38]3 years ago
3 0
   I'm sorry for the inconvenience but can you put a picture a visual image for me to look at so I can go into further analysis and answer the question that you have provided. If you are having trouble with doing that, reach out for help and i will be glad to assist you. :)

That would be greatly appreciated for your kindness :)
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Can anyone help me with my homework?
Evgesh-ka [11]

I want more points next time....Hehehee!

<h2><u>______________________</u></h2>

<em>Solution in attachments!</em>

6 0
2 years ago
Convert 550cm to meters
Viefleur [7K]

1 meter = 100 cm

550/100 = 5.5

 5.5 meters

4 0
3 years ago
Help me on number 44 plz
Delvig [45]
All you have to do is write a positive number. let's say 4, then write a positive exponent (that's the tiny number in the right corner of the regular number) and then just write a positive exponent less than 4.
So 4 squared
4 0
3 years ago
let x1,x2, and x3 be linearly independent vectors in R^(n) and let y1=x2+x1; y2=x3+x2; y3=x3+x1. are y1,y2,and y3 linearly indep
Nutka1998 [239]

Answer with Step-by-step explanation:

We are given that

x_1,x_2 and x_3 are linearly independent.

By definition of linear independent there exits three scalar a_1,a_2 and a_3 such that

a_1x_1+a_2x_2+a_3x_3=0

Where a_1=a_2=a_3=0

y_1=x_2+x_1,y_2=x_3+x_2,y_3=x_3+x_1

We have to prove that y_1,y_2 and y_3 are linearly independent.

Let b_1,b_2 and b_3 such that

b_1y_1+b_2y_2+b_3y_3=0

b_1(x_2+x_1)+b_2(x_3+x_2)+b_3(x_3+x_1)=0

b_1x_2+b_1x_1+b_2x_3+b_2x_2+b_3x_3+b_3x_1=0

(b_1+b_3)x_1+(b_2+b_1)x_2+(b_2+b_3)x_3=0

b_1+b_3=0

b_1=-b_3...(1)

b_1+b_2=0

b_1=-b_2..(2)

b_2+b_3=0

b_2=-b_3..(3)

Because x_1,x_2 and x_3 are linearly independent.

From equation (1) and (3)

b_1=b_2...(4)

Adding equation (2) and (4)

2b_1==0

b_1=0

From equation (1) and (2)

b_3=0,b_2=0,b_3=0

Hence, y_1,y_2 and y_3 area linearly independent.

5 0
3 years ago
Simultaneously x-2y=0 40-y=14​
harkovskaia [24]

Answer:

x = 52, y = 26

Step-by-step explanation:

x - 2y = 0

40 - y = 14​

(40 - 40) - y = 14​ - 40

- y = -26

y = 26

x - 2(26) = 0

x - 52 = 0

x (- 52 + 52) = 0 + 52

x = 52

7 0
3 years ago
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