Here...see the attachment
Answer: x=1,y=0
Step-by-step explanation:
X-2y=1.....equation 1
2x-y=2.....equation 2
X=1+2y.......equation 3
Substitute equation 3into 2
2(1+2y)-y=2
2+4y-y=2
2+3y=2
3y=2-2
3y=0
Y=0/3
Y=0
Substitute for y=0 in equation 1
X-2y=1
X-2(0)=1
X-0=1
X=1
X=1 & Y=0
12.5×12.5 will give u 42 an if u add it u will get 25
Answer:
135 degrees

Step-by-step explanation
Consider the attached diagram
we are required to find the bearing of the aeroplane,
Consider the right angled triangle BOE
|OB|=4 unit
|AB|=4 Units

The Bearing of the Aeroplane is therefore given:
(i)From North Clockwise as: 90+45 =135 degrees
(ii)From a North South Line as
I think it is 10.
hope this helps!!! :D