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MariettaO [177]

3 years ago

10

What is the slope of this graph? A. −14 B. 4 C.−4 D. 14

2 answers:

DiKsa [7]3 years ago

6 0

What graph are you talking about:? can you give a pivture

Anna007 [38]3 years ago

3 0

I'm sorry for the inconvenience but can you put a picture a visual image for me to look at so I can go into further analysis and answer the question that you have provided. If you are having trouble with doing that, reach out for help and i will be glad to assist you. :)

That would be greatly appreciated for your kindness :)

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Complete the table below.<br> HeLPP ILL GIVE BRAINLIEST!

makkiz [27]

Here...see the attachment

6 0

2 years ago

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Solve simultaneous equation <br> X-2y=1<br> 2x-y=2

Step2247 [10]

Answer: x=1,y=0

Step-by-step explanation:

X-2y=1.....equation 1

2x-y=2.....equation 2

X=1+2y.......equation 3

Substitute equation 3into 2

2(1+2y)-y=2

2+4y-y=2

2+3y=2

3y=2-2

3y=0

Y=0/3

Y=0

Substitute for y=0 in equation 1

X-2y=1

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7 0

2 years ago

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What two numbers multiply to get 42 and add to get 25

Nataly_w [17]

12.5×12.5 will give u 42 an if u add it u will get 25

6 0

2 years ago

An observer for a radar station is located at the origin of a coordinate system. Find the bearing of an airplane located at the

AfilCa [17]

Answer:

135 degrees

$S45^{0}E$

Step-by-step explanation

Consider the attached diagram

we are required to find the bearing of the aeroplane,

Consider the right angled triangle BOE

|OB|=4 unit

|AB|=4 Units

$Tan \alpha =\frac{Opposite}{Adjacent} =\frac{4}{4} \\\\\alpha=Tan^{-1} 1=45 degrees$

The Bearing of the Aeroplane is therefore given:

(i)From North Clockwise as: 90+45 =135 degrees

(ii)From a North South Line as $S45^{0}E$

6 0

3 years ago

HELP ME PLEASE FOR BRAINLIEST!!!!

Brilliant_brown [7]

I think it is 10.

hope this helps!!! :D

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2 years ago