Question

s in this population? In a population of 100 individuals, 50 are genotype MM, 40 are MN, and 10 are NN. What are the frequencies of the M and N alleles in this population? f(M) = 0.5, f(N) = 0.5 f(M) = 0.1, f(N) = 0.9 f(M) = 0.9, f(N) = 0.1 f(M) = 0.3, f(N) = 0.7 f(M) = 0.7, f(N) = 0.3

Answer 1

Answer:

F(M) = 0.7 F(N)=0.3

Explanation:

We need to take into account that individuals NN and MM only N or M aleles respectively while MN gives just half of the allelic contribution for each. With this in mind we have the following probabilities for getting each of the alleles: MM => p(M) = 1.0 and p(N)=0.0

MN => p(M ) = 0.5 and p(N) = 0.5

NN => P(M) = 0.0 and p(N) = 1.0

With this we can calculate the frequencies of the M and N alleles in the population with 100 individuals using the following formulas

For f(M):

$f(M)=\frac{1.0 (MM) + 0.5 (MN)}{Total individuals}$

$f(M)=\frac{1.0(50)+0.5(40)}{100}$

$f(M) = \frac{50+20}{100}$

$f(M)=\frac{70}{100}=\frac{7}{10}=0.7$

The frequency of the M allele is 0.7

For f(N):

$f(N)=\frac{1.0 (NN) + 0.5 (MN)}{Total individuals}$

$f(N)=\frac{1.0(10)+0.5(40)}{100}$

$f(N) = \frac{10+20}{100}$

$f(M)=\frac{30}{100}=\frac{3}{10}=0.3$

The frequency of the N allele is 0.3