Malika owns a small business selling bagels. She knows that in the last week 63

Let the given points be the endpoints of a right triangle. The horizontal change in x is from 4 to -5 and is negative 9; the vertical change in y is from -2 to+ 3 and is +5.

The desired distance is found using the Pythagorean theorem:

d = √(9² + 5²) = √106, or 10.3 (to the nearest tength)

3 0

2 years ago

How do i write y = x -4 in a x and y chart/table?

IrinaK [193]

Okay well it kept saying that I for some reason was not using appropriate words so my long response got deleted.

tldr; we can treat this like a box that we put something into (x) and we get something back from it (y).

We can then take this data we get and put it in a table. This is useful for finding patterns.

I will post a picture of what a table may look like.

Hope this Helps!

6 0

3 years ago

"A study of the amount of time it takes a mechanic to rebuild the transmission for a 2005 Chevrolet Cavalier shows that the mean

Arada [10]

Answer:

85.31% probability that their mean rebuild time exceeds 8.1 hours.

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central limit theorem:

The Central Limit Theorem estabilishes that, for a random variable X, with mean $\mu$ and standard deviation $\sigma$ , the sample means with size n of at least 30 can be approximated to a normal distribution with mean $\mu$ and standard deviation $s = \frac{\sigma}{\sqrt{n}}$