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3 years ago

6

“If f(x) and it’s inverse function, f^-1(x), are both plotted on the same coordinate plane, where is their point of intersection

?”

1 answer:

Ghella [55]3 years ago

7 0

Answer:

it is not always possible to find their intersection point for e.g take

y=x-1 it's inverse is y=x+1 so their is no intersection point but generally u find intersection points by equalizing their functions

f(x)=f^-1(x)

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How do u divide fractions

8090 [49]

For example 5/10\1/2 you would keep the 5/10 and flip the 1/2 to 2/1 and then multiply 5\10x2/1 to get 10/10 so 1

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2 years ago

A store pays $10.56 fora map of Africa and marks the price up by

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2 years ago

What is the value of the square root of 36

irakobra [83]

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Like how $6^{2}$ = 36

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2 years ago

Read 2 more answers

Find the slope of the line

olga55 [171]

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2 years ago

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To complete this component you will need to insert parentheses in Expression 2 to change the order of operations so the expressi

Alika [10]

Given:

The expression is $5+4\times 2+6-2\times 2-1$ .

To find:

The position of parentheses inserted in the expression to get the value 19

Step-by-step explanation:

We have,

$5+4\times 2+6-2\times 2-1$

Now,

$(5+4)\times 2+6-2\times 2-1=9\times 2+6-4-1$

$(5+4)\times 2+6-2\times 2-1=18+6-5$

$(5+4)\times 2+6-2\times 2-1=18+1$

$(5+4)\times 2+6-2\times 2-1=19$

There are more ways to apply the parenthesis, but we do not get 19.

$5+4*\left(2+6\right)-2*2-1=32\neq 19$

$5+4*2+\left(6-2\right)*2-1=20\neq 19$

$5+4*2+6-2*\left(2-1\right)=17\neq 19$

And many more possibilities.

Therefore, the expression after inserting the parentheses is $(5+4)\times 2+6-2\times 2-1$ .

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2 years ago