Complete Question
The length of the guy wire supporting a cell tower is 120 m. The guy wire is anchored to the ground at a distance of 80 m from the base of the tower to the nearest hundredth of a meter how tall is the tower?
Answer:
89.44m
Step-by-step explanation:
We solve this question using the Pythagoras Theorem
This is given as:
Hypotenuse² = Opposite ² + Adjacent ²
Hypotenuse = Length of the guy wire = 120m
Adjacent = Distance from the base of the tower = 80m
Opposite = Height of the building = x
Hence:
120² = x² + 80²
Collect like terms
x² = 120² - 80²
x = √120² - 80²
x = √(8000)
x = 89.4427191 m
Approximately the height of the tower is = 89.44m
The answer will be -22x^2-14x. Hope it help!
Answer:
0.05357142
Step-by-step explanation:
Answer:
10.05 meters
Step-by-step explanation:
If the diameter is 3.2 meters, then the radius is 1.6 meters.
Use the circumference formula, C = 2
r, and solve for C
C = 2
r
C = 2
(1.6)
C = 3.2
C = 10.05
So, to the nearest hundredth of a meter, the circumference is 10.05 meters
Answer:
$2561.99 a quarter
Step-by-step explanation:
Just add together what they pay every year, then multiply by 25.5% (because that's the quarterly premium.)
Annual cost = insurance + dental + vision
= 8900 + 772 + 375 = $10047 a year.
Quarterly cost = 25.5% of annual cost
Whenever you see of, think of multiplication!
25.5% = .255
Quarterly cost = .255 * 10047 = <u>$2561.99 a quarter</u>