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Shalnov [3]
3 years ago
10

List all of the two digit numbers that can be made using the digits 5,7,and 8

Mathematics
1 answer:
LuckyWell [14K]3 years ago
3 0

9514 1404 393

Answer:

  57, 58, 75, 78, 85, 87 (no repeats)

  add 55, 77, 88 to the above list if repeats are allowed.

Step-by-step explanation:

With no repeating digits, there are 3 ways to choose the first digit, and 2 ways to choose the second digit, for a total of 3×2 = 6 possible numbers

  57, 58, 75, 78, 85, 87

If the digits can be repeated, than you can add 55, 77, 88 to that list:

  55, 57, 58, 75, 77, 78, 85, 87, 88

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3 years ago
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suter [353]
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There are two ways to do this. You can try the four options by seeing where they lie on the graph, or by inputting them into the inequality and seeing if they check out. I am going to do a bit of both.

I know that the solution cannot have two positive coordinates because the first quadrant is not part of the solution, so I won't guess A or C. 
I'll try (3, –2) (which is option B).
On the graph, (3, –2) is on the line, which means it is part of the solution because the line is solid and the inequality is a greater than or equal to sign. 
Try it in the inequality: 
y ≤ –x + 1 
–2 ≤ –3 + 1 
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