Answer:
518
i don't know if this needs much explaining.
Membership is discounted $2 for first month
c=cost of one month
d=discount=$2
x=# of months
xc - 2= total cost
x for 1 month is 1, c is always 12, -2 is constant
1 x(12) - 2=10 for first month
8 months
8c -2=total cost for 8 months
8 x 12 - 2= 94 for 8 months
Answer:
y=10
Step-by-step explanation:
8(7-y) =-24
WE APPLY DISTRIBUTIVE PROPERTY:
8*7 -8*y =-24
56 -8y=-24
56+24=8y
80 = 8y
y=80/8
y=10
Answer:1. $3- 4 bottles, 1 bottle = 4/3 , 7 bottles= 28/3
2. 40 pounds=$32, 1 pound= $8/10
3. Per bag= 3/2, 7bags= 21/2
4. Per book = $3, 21 books= $63
5. Per bracelet = 0.25 cents, 11 bracelets = 2 dollars 75 cents
Step-by-step explanation:
If inspection department wants to estimate the mean amount with 95% confidence level with standard deviation 0.05 then it needed a sample size of 97.
Given 95% confidence level, standard deviation=0.05.
We know that margin of error is the range of values below and above the sample statistic in a confidence interval.
We assume that the values follow normal distribution. Normal distribution is a probability that is symmetric about the mean showing the data near the mean are more frequent in occurence than data far from mean.
We know that margin of error for a confidence interval is given by:
Me=
α=1-0.95=0.05
α/2=0.025
z with α/2=1.96 (using normal distribution table)
Solving for n using formula of margin of error.

n=
=96.4
By rounding off we will get 97.
Hence the sample size required will be 97.
Learn more about standard deviation at brainly.com/question/475676
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The given question is incomplete and the full question is as under:
If the inspection division of a county weights and measures department wants to estimate the mean amount of soft drink fill in 2 liters bottles to within (0.01 liter with 95% confidence and also assumes that standard deviation is 0.05 liter. What is the sample size needed?