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Rufina [12.5K]
2 years ago
11

Sierra makes frozen juice bars. she uses 3/8 cup of orange juice for each bar. how many cups of orange juice does she need to ma

ke 6 bars?
Mathematics
1 answer:
Minchanka [31]2 years ago
3 0
Sierra is thirsty dammit
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A record store has 3,108 records evenly shared among 6 rows. How many records are in each row?
PilotLPTM [1.2K]

Answer:

518

i don't know if this needs much explaining.

3 0
2 years ago
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A racquetball club charges $10 for a one-month trial membership. After the trail month, the regular membership fee is $12 per mo
Furkat [3]
Membership is discounted $2 for first month
c=cost of one month
d=discount=$2
x=# of months
xc - 2= total cost
x for 1 month is 1, c is always 12, -2 is constant
1 x(12) - 2=10 for first month
8 months
8c -2=total cost for 8 months
8 x 12 - 2= 94 for 8 months

5 0
3 years ago
Solve for y plzzz !!​
max2010maxim [7]

Answer:

y=10

Step-by-step explanation:

8(7-y) =-24

WE APPLY DISTRIBUTIVE PROPERTY:

8*7 -8*y =-24

56 -8y=-24

56+24=8y

80 = 8y

y=80/8

y=10

3 0
3 years ago
1. Twelve large bottles of water cost $9.
Vaselesa [24]

Answer:1. $3- 4 bottles, 1 bottle = 4/3 , 7 bottles= 28/3

2. 40 pounds=$32, 1 pound= $8/10

3. Per bag= 3/2, 7bags= 21/2

4. Per book = $3, 21 books= $63

5. Per bracelet = 0.25 cents, 11 bracelets = 2 dollars 75 cents

Step-by-step explanation:

4 0
3 years ago
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If the inspection division of a county weights and measures department wants to estimate the mean amount of
Amanda [17]

If inspection department wants to estimate the mean amount with 95% confidence level with standard deviation 0.05 then it needed a sample size of 97.

Given 95% confidence level, standard deviation=0.05.

We know that margin of error is the range of values below and above the sample statistic in a confidence interval.

We assume that the values follow normal distribution. Normal distribution is a probability that is symmetric about the mean showing the data  near the mean are more frequent in occurence than data far from mean.

We know that margin of error for a confidence interval is given by:

Me=z/2* ST/\sqrt{N}

α=1-0.95=0.05

α/2=0.025

z with α/2=1.96 (using normal distribution table)

Solving for n using formula of margin of error.

n=(z/2ST/Me)^{2}

n=(1.96*0.05)^{2} /(0.01)^{2}

=96.4

By rounding off we will get 97.

Hence the sample size required will be 97.

Learn more about standard deviation at brainly.com/question/475676

#SPJ4

The given question is incomplete and the full question is as under:

If the inspection division of a county weights and measures department wants to estimate the mean amount of soft drink fill in 2 liters bottles to within (0.01 liter with 95% confidence and also assumes that standard deviation is 0.05 liter. What is the sample size needed?

7 0
2 years ago
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