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3 years ago

5. Write the number in expanded form using exponents. 2,036,017

Mathematics

1 answer:

tiny-mole [99]3 years ago

3 0

Answer:

See below.

Step-by-step explanation:

I think you mean:

2*10^6 + 3*10^4 + 6*10^3 + 1 * 10^1 + 7.

I hope this helps.

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dezoksy [38]

Step-by-step explanation:

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2 years ago

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A scale reports a 15-pound weight as weighing 12.375 pounds.

Kruka [31]

B. Accuracy is if it's right or not. Precision is how many decimal places it goes out to. So it is precise but not accurate.

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3 years ago

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For her college fund jenny's parents invested $5000 four years ago. the account has now reached $6312. what is the approximate a

Tasya [4]

Answer:

Rate = 6.56%

Step-by-step explanation:

Principal (P) = $5000

Interest (I) = $6312

Time (T) = 4 years

Rate (r) = ?

This question is involves simple interest and with the formula, we can easily plug in the values to find the rate.

S.I = P(1 + rt)

S.I = simple interest

P = principal

R = Rate

T = Time

6312 = 5000(1 + r*4)

6312 = 5000 + 5000*4r

6312 - 5000 = 20000r

1312 = 20000r

r = 1312 / 20000

r = 0.0656

Rate are calculated in percentage hence we'll multiply it by 100

R = 6.56%

4 0

3 years ago

Solve the compound inequality 6b < 24 or 4b + 12 > 4.

myrzilka [38]

The answer is a. b>-2 because

6b<24
b< 24/6
b<4

And

4b+12>4
4b>4-12
4b>-8
b>-8/4
b>-2

3 0

3 years ago

An ice cube is melting, and the lengths of its sides are decreasing at a rate of 0.8 millimeters per minute At what rate is the

julia-pushkina [17]

Answer:

The rate of decrease is: $43.2mm^3/min$

Step-by-step explanation:

Given

$l = 18mm$

$\frac{dl}{dt} = -0.8mm/min$ ---- We used minus because the rate is decreasing

Required

Rate of decrease when: $l = 18mm$

The volume of the cube is:

$V = l^3$

Differentiate

$\frac{dV}{dl} = 3l^2$

Make dV the subject

$dV = 3l^2 \cdot dl$

Divide both sides by dt

$\frac{dV}{dt} = 3l^2 \cdot \frac{dl}{dt}$

Given that: $l = 18mm$ and $\frac{dl}{dt} = -0.8mm/min$

$\frac{dV}{dt} = 3 * (18mm)^2 * (-0.8mm/min)$

$\frac{dV}{dt} = 3 * 18 *-0.8mm^3/min$

$\frac{dV}{dt} = -43.2mm^3/min$

<em>Hence, the rate of decrease is: 43.2mm^3/min</em>

8 0

3 years ago