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natta225 [31]
4 years ago
13

What is the answer to this I can’t figure it out !

Mathematics
2 answers:
svetlana [45]4 years ago
7 0
4 = ones
5 = tens
8 = tenths
9 = hundredths
7 = thousandths
Ksju [112]4 years ago
4 0

It's asking what place value those numbers are in the number above. For example, the 4 is in the ones place. The 5 is in the tens place. Try the 8.

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The equation of a circle is x^2+(y+4)^2=1<br> What are it’s center and it’s radius?
AnnZ [28]

Answer:

see attachment

Step-by-step explanation:

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3 years ago
The value of the digit 5 in 24,513 is how many times the value of the 5 in 357?
olchik [2.2K]
24,513 500
357 50
500/50 = 10
10 times greater
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3 years ago
2 sides of triangle measure 20 cm &amp; 30 cm what is 3rd side?
Gnesinka [82]
-------------------------36.06
4 0
3 years ago
PLEASE HELP ME WITH THIS 17 points!! PLEASEEEE IM BEGGING YOU!!!
slega [8]

Answer:

x = 2

Step-by-step explanation:

Step 1: Convert to math

5x + 1 = 3x + 5

Step 2: Solve for <em>x</em>

  1. Subtract 4x on both sides: 2x + 1 = 5
  2. Subtract 1 on both sides: 2x = 4
  3. Divide both sides by 2: x = 2

Step 3: Check

<em>Plug in x to verify it's a solution.</em>

5(2) + 1 = 3(2) + 5

10 + 1 = 6 + 5

11 = 11

7 0
3 years ago
Read 2 more answers
Circle O, with center (x, y), passes through the points A(0, 0), B(–3, 0), and C(1, 2). Find the coordinates of the center of th
balandron [24]
The answer:

the main formula of the circle's equation is 
(x-a)²+ (y-b)² = R²
where C(a, b) is the center of the circle
R is the radius

if a point A(x', y') passes through the circle, so the equation of the circle can be written as 
(x'-a)²+ (y'-b)² = R², and that is  a main formula.


<span>Circle O, with center (x, y), passes through the points A(0, 0), B(–3, 0), and C(1, 2), so we have exactly three equation:
</span>
(0-x)² + (0-y)² = R², circle O passes through A
x²+y²= R²
(-3 -x)² + (0-y)² = R², circle O passes through B
(-3 -x)² + (y)² = R²
(1-x)² + (2-y)² = R², circle O passes through A
(1-x)² + (2-y)² = R²

and we know that R= OA = OC= OB, 
OA=R= sqrt( (0-x)² + (0-y)² ) = OB = sqrt((-3 -x)² + (0-y)²), this implies

x²+y² = (-3 -x)² + (0-y)² , it implies x² = 9+ x² + 6x , and then -9/6=x, x= -3/2
and when OA = OC
x²+y² =(1-x)² + (2-y)²  so, x²+y² =1+x²-2x +4+y²-4y, therefore -5= -2x -4y
 -5= -2x -4y, when x = -3 /2   we obtain y = 2

the center is C(-3/2, 2)
7 0
4 years ago
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