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Anastasy [175]
3 years ago
10

Use the number line to determine whether the two fractions 1/2, 4/8 are equivalent. Yes or no.

Mathematics
1 answer:
musickatia [10]3 years ago
7 0
You could do that (yes), but in many cases, you would need to determine equivalence some other way (no) before plotting the numbers on a number line.

If the number line is graduated in a manner that makes 1/2 clear, and also makes 4/8 clear, then it is possible to determine that both values lie at the same point. If the number line is graduated in tenths or hundredths (for example), you would need to convert both numbers to that format before plotting.

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Com babes<br> bdx-fnbi-zfx
Oksi-84 [34.3K]

Answer:

Yes

Step-by-step explanation:

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What's the slope of (-2,-1) and (4,3)
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Answer:

4/6

Step-by-step explanation:

→ Write the slope formula

(y₂ - y₁) ÷ (x₂ - x₁)

→ Substitute in the numbers

(3 - -1) ÷ (4 - -2)

→ Simplify

4/6

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What is the equation of a line that has a slope of 4/5 and passes through the point (-2,4)?
SOVA2 [1]

Answer:

y = \frac{4}{5}x + 5\frac{3}{5}

Step-by-step explanation:

Let's do it in slope-intercept form, it will look like this:

m = slope

b = y -intercept

To find our equation we will plug in the slope, plug in the point given, and solve for b.

y = mx + b

y = \frac{4}{5}x + b

4 = \frac{4}{5}(-2) + b

4 = -\frac{8}{5} + b

5\frac{3}{5} = b

Plug the b into our original equation, and there is our answer!

y = \frac{4}{5}x + 5\frac{3}{5}

7 0
2 years ago
Express the series using sigma notation. 6 + 9 + 12 + 15.<br><br> a<br> b<br> c<br> d
Nadusha1986 [10]

Answer:

Option (d) is correct.

6 + 9 + 12 +15 = \sum_{k=1}^{4}(3k+3)

Step-by-step explanation:

Consider the given series expansion 6 + 9 + 12 +15.

since we have to write in series form of 3.

We first write each term of given series in term of 3k or 3k+3

6 can be written as 3(2) or 3(1)+3

9 can be written as 3(3) or 3(2)+3

12 can be written as 3(4) or 3(3)+3

15 can be written as 3(5) or 3(4)+3

Thus, we can write the given series as ,

\sum_{k=2}^{5}3k or  \sum_{k=1}^{4}(3k+3)

Since, we have options to choose.

From the given option (d) matches our result.

So,  6 + 9 + 12 +15 = \sum_{k=1}^{4}(3k+3)


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3 years ago
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A=p(1+i/m)^mn
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