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Stells [14]
2 years ago
6

At a college, 71% of courses have final exams and 45% of courses require research papers. Suppose that 26% of courses have a res

earch paper and a final exam.
Part (a)

Find the probability that a course has a final exam or a research paper.


Part (b)

Find the probability that a course has neither of these two requirements.
Mathematics
1 answer:
Degger [83]2 years ago
3 0

Answer:

.9 or 90%

.1 or 10%

Step-by-step explanation:

E= Exam

P=Paper

E= .71

P= .45

E∩P=.26

A.) E∪P=?

E∪P= E+P-E∩P

.71+.45-.26= .9

B.) E'∩P' = (E∪P)'

(E∪P)' = 1-.9 = .1

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Bessie has an annual salary of $51,360. Each month she has a car payment of $210 and a student loan of$50. If she applies for a
Svetach [21]
Every month she makes 4280 usd. $51,360/12 months...she pays her debt ($260) a month.....she will be approved. 1:16 Ratio
6 0
3 years ago
Graph the following three equations on your own device and answer the questions below.
Alina [70]

Due to length restrictions, we kindly invite to read the explanation of this question for further details on functions.

<h3>What are the characteristics of each of the three functions?</h3>

a) In this part we must evaluate each of the three functions at the given value of x:

Case 1

f(10) = 5 · 10 + 7

f(10) = 57

Case 2

f(10) = 10² + 6

f(10) = 106

Case 3

f(10) = 2¹⁰ + 3

f(10) = 1027

b) In this part we must evaluate each of the three functions at the given value of x:

Case 1

f(100) = 5 · 100 + 7

f(100) = 507

Case 2

f(100) = 100² + 6

f(100) = 10006

Case 3

f(100) = 2¹⁰⁰ + 3

f(100) = 1.267 × 10³⁰ + 3

c) In this part we must evaluate each of the three functions at the given value of x:

Case 1

f(1000) = 5 · 1000 + 7

f(1000) = 5007

Case 2

f(1000) = 1000² + 6

f(1000) = 1000006

Case 3

f(1000) = 2¹⁰⁰⁰ + 3

f(1000) = (1.268 × 10³⁰)¹⁰ + 3

f(1000) = 10.744 × 10³⁰⁰ + 3

f(1000) = 1.074 × 10³⁰¹ + 3

e) The <em>third</em> function increases the fastest.

f) In this part we need to compare the <em>third</em> function with respect to the <em>first</em> and <em>second</em> functions:

5 · x + 7 = 2ˣ + 3

2ˣ - 5 · x   = 4

The solutions of the equation are x = - 0.675 and x = 4.81. The function will exceed the other <em>first</em> function at x = 4.81.

x² + 6 = 2ˣ + 3

2ˣ - x² = 3

The solution of the equation is x = 4.588. The function will exceed the other <em>second</em> function at x = 4.588.

g) Yes, <em>exponential</em> functions with bases greater than 1 will surpass <em>polynomic</em> function at any point x such that x > 0.

h) The domain represents the set of x-values of a function and the range represents the set of y-values of a function. Then, the domain and range of each function is:

Case 1

Domain - All <em>real</em> numbers.

Range - All <em>real</em> numbers

Case 2

Domain - All <em>real</em> numbers.

Range - [6, +∞)

Case 3

Domain - All <em>real</em> numbers.

Range - (3, +∞)

To learn more on functions: brainly.com/question/12431044

#SPJ1

5 0
1 year ago
The volume of a right rectangular prism can be found by using the product 9(4)(1.1). Which expression could also be used to dete
love history [14]

Answer:The answer is A)11(9)(4)

Step-by-step explanation:

If you have 9(4)(11) then is would be the one that look just like it but the number are moved like 11(9)(4)

8 0
2 years ago
Read 2 more answers
In isosceles right triangle ABC, point is on hypotenuse \overline{BC} such that \overline{AD} is an altitude of \triangle ABC an
Dmitriy789 [7]

Answer:

Area of triangle is 25.

Step-by-step explanation:

We have been given an isosceles right triangle

Isosceles triangle is the triangle having two sides equal.

Figure is shown in attachment

By Pythagoras theorem

BC^2=AC^2+AB^2

AD is altitude which divides the triangle into two parts

DC=5 implies BC =10 since D equally divides BC

Let AC=a implies AB=a being Isosceles

On substituting the values in the Pythagoras theorem:

10^2=a^2+a^2

100=2a^2

\Rightarrow a^2=50

\Rightarrow a=\pm5\sqrt{2}

WE can find area of right triangle by considering height AB and AD

Area of triangle ABC is:

\frac{1}{2}\cdot BC\cdot AD     (1)

\Rightarrow \frac{1}{2}\cdot 10\cdot AD

And other method of area of triangle is:

\frac{1}{2}\cdot AB\cdot BC       (2)

Equating (1) and (2) we get:

\frac{1}{2}\cdot 10\cdot AD=\frac{1}{2}\cdot a\cdot a

\Rightarrow AD=\frac{a^2}{10}

\Rightarrow AD=\frac{50}{10}=5

Using area of triangle is: \frac{1}{2}\cdot BC\cdot AD

Now, the area of triangle ABC=\frac{1}{2}\cdot 5\cdot 10

\Rightarrow 25



4 0
3 years ago
Do you guys now the answer I need it ASAP please
HACTEHA [7]

Answer:I think that it would be either b or c

Step-by-step explanation:

4 0
2 years ago
Read 2 more answers
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