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Stells [14]
3 years ago
6

At a college, 71% of courses have final exams and 45% of courses require research papers. Suppose that 26% of courses have a res

earch paper and a final exam.
Part (a)

Find the probability that a course has a final exam or a research paper.


Part (b)

Find the probability that a course has neither of these two requirements.
Mathematics
1 answer:
Degger [83]3 years ago
3 0

Answer:

.9 or 90%

.1 or 10%

Step-by-step explanation:

E= Exam

P=Paper

E= .71

P= .45

E∩P=.26

A.) E∪P=?

E∪P= E+P-E∩P

.71+.45-.26= .9

B.) E'∩P' = (E∪P)'

(E∪P)' = 1-.9 = .1

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Nookie1986 [14]

Answer:

z = 3.2 units

Step-by-step explanation:

sin 76°/z = sin 51°/2.6

cross-multiply to get:

z·(sin 51°) = 2.6·(sin 76°)

z = 2.6·(sin 76°) ÷ (sin 51°)

z = 3.2

3 0
3 years ago
Explain what |-13| means and how to simplify.
poizon [28]

The two bars ( | | ) symbolize absolute value

Absolute value is essentially just making the number given positive.

If the given number is already positive then the absolute value is the same as the original number

|-13| is 13

The absolute value of -13 is 13

Hope this helped!

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4 0
3 years ago
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Keith_Richards [23]

Answer:

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Step-by-step explanation:

8 0
3 years ago
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Use quadratic regression to find
Rashid [163]

The quadratic equation is given by:

y = 3x² + 10x - 8

The standard equation of a parabola is given by:

y = ax² + bx + c

Where a, b, c are constants

At point (4, 80):

80 = a(4)² + b(4) + c

16a + 4b + c = 80     (1)

At point (-3, -11):

-11 = a(-3)² + b(-3) + c

9a - 3b + c = -11     (2)

At point (-1, -15):

-15 = a(-1)² + b(-1) + c

a - b + c = -15     (3)

Solving equations 1, 2 and 3 simultaneously gives:

a = 3, b = 10, c = -8

Therefore the quadratic equation becomes:

y = 3x² + 10x - 8

Find out more on quadratic equation at: brainly.com/question/1214333

8 0
2 years ago
What is 2,605 rounded to the nearest hundred
AveGali [126]
2,600 is the answer to your question
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3 years ago
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