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pav-90 [236]
3 years ago
9

A polynomial function has a zero at x=3 which of the follwing expressions must be one factor of the polynomial. A. x + 3 b. 3x C

. x^3 D. x - 3 but could you explain how to do it so i can do it on my own! ...?
Mathematics
2 answers:
nexus9112 [7]3 years ago
5 0
I think the correct answer from the choices listed above is option D. A polynomial function has a zero value at x=3 for the <span>expression where one factor is x-3. This factor when x=3 will always result to a zero value no matter what you multiply to it. Hope this answers the question.</span>
r-ruslan [8.4K]3 years ago
5 0

Answer:  The correct option is (D) (x - 3).

Step-by-step explanation:  Given that a polynomial function has a zero at x = 3.

We are to select the correct expression that must be a factor of the polynomial.

<em><u>FACTOR THEOREM :  </u></em> The theorem states that if x = a is a zero of a polynomial p(x), then (x - a) will be a factor of the polynomial p(x).

In case of our given polynomial, since x = 3 is a zero of the polynomial, so by factor theorem, we can say that

(x - 3) is a factor of the given polynomial.

Thus, the required factor is (x - 3).

Option (D) is CORRECT.

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Elenna [48]

Given:

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To find:

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Center=\left(\dfrac{x_1+x_2}{2},\dfrac{y_1+y_2}{2}\right)

Center=\left(\dfrac{0+4}{2},\dfrac{0+(-6)}{2}\right)

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Therefore, the standard form of the circle is (x-2)^2+(y+3)^2=13.

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The way to solve this question is to essentially reverse the equation I used in the other answer.


I would solve this with some theoretical values. If you start with 3, how long would it take for it to triple, or reach 9.


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