Question not well presented
Point S is on line segment RT . Given RS = 4x − 10, ST=2x−10, and RT=4x−4, determine the numerical length of RS
Answer:
The numerical length of RS is 22
Step-by-step explanation:
Given that
RS = 4x − 10
ST=2x−10
RT=4x−4
From the question above:
Point S lies on |RT|
So, RT = RS + ST
Substitute values for each in the above equation to solve for x
4x - 4 = 4x - 10 + 2x - 10 --- collect like terms
4x - 4 = 4x + 2x - 10 - 10
4x - 4 = 6x - 20--- collect like terms
6x - 4x = 20 - 4
2x = 16 --- divide through by 2
2x/2 = 16/2
x = 8
Since, RS = 4x − 10
RS = 4*8 - 10
RS = 32 - 10
RS = 22
Hence, the numerical length of RS is calculated as 22
Step-by-step explanation:
they forget the last step which is to take the square root of the sum
7) a = 4
b = 17
a² + b² = c²
4²+ 17² = c²
16 + 289 = c²
305 = c²
√305 = c
17.464249196572980 = C
Increasing. For every week that goes by, Olivia's puppy is gaining one pound. 6-5= 1 14-13= 1. Gaining a pound every week makes the puppies weight increase. Since increase is the term for something is bigger than number or value than before, Olivia's puppies' weight is increasing.
I hope this helps!
~kaikers
To solve for proportion we make use of the z statistic.
The procedure is to solve for the value of the z score and then locate for the
proportion using the standard distribution tables. The formula for z score is:
z = (X – μ) / σ
where X is the sample value, μ is the mean value and σ is
the standard deviation
when X = 70
z1 = (70 – 100) / 15 = -2
Using the standard distribution tables, proportion is P1
= 0.0228
when X = 130
z2 = (130 – 100) /15 = 2
Using the standard distribution tables, proportion is P2
= 0.9772
Therefore the proportion between X of 70 and 130 is:
P (70<X<130) = P2 – P1
P (70<X<130) = 0.9772 - 0.0228
P (70<X<130) = 0.9544
Therefore 0.9544 or 95.44% of the test takers scored
between 70 and 130.
