Matter is in a liquid state when its temperature is between its melting point and its boiling point. Suppose that some substance
has a melting point of negative 37.57 degrees Upper C and a boiling point of 389.96 degrees Upper C. What is the range of temperatures in degrees Fahrenheit for which this substance is not in a liquid state? (Hint: Upper C equals five ninths left parenthesis Upper F minus 32 right parenthesis ) Express the range as an inequality and in interval notation.
1 answer:
Answer:
-35.626 < temperature < 733.928 . . . . degrees F
(-35.626, 733.928)
Step-by-step explanation:
It is convenient to let a calculator evaluate the expression for converting °C to °F.
-35.626 < temperature < 733.928 . . . . degrees F
(-35.626, 733.928) . . . . . . . . . . . . . . . . . in interval notation
_____
The given relation is C = 5/9(F -32). The inverse relation is F = 9/5C +32. That is the relation we need to use to answer this question.
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Answer:
(a) 35 heads correspond to -3 on the standard scale.
(b) z = 2.4 corresponds to 62 heads on the number of heads scale.
Step-by-step explanation:
(a) If we flip a fair coin once, probability of getting head = 0.5
If we flip a fair coin 100 times, mean number of heads = 100(0.5) = 50
If there are N draws with a P probability of success, the standard deviation (SD) is given as:
Here, the probability of getting a head (P) is 0.5 while the number of draws (N) is 100. So,
SD = 5
The standard scale value is: (35 - 50) / 5 = -3
Hence, 35 heads correspond to -3 on the standard scale.
(b) The standard scale value is 2.4 and we need to find the number of heads.
(X - 50) / 5 = 2.4
X - 50 = 12
X = 62
Hence, z = 2.4 on the standard scale corresponds to 62 on the number of heads scale.