Matter is in a liquid state when its temperature is between its melting point and its boiling point. Suppose that some substance
has a melting point of negative 37.57 degrees Upper C and a boiling point of 389.96 degrees Upper C. What is the range of temperatures in degrees Fahrenheit for which this substance is not in a liquid state? (Hint: Upper C equals five ninths left parenthesis Upper F minus 32 right parenthesis ) Express the range as an inequality and in interval notation.
1 answer:
Answer:
-35.626 < temperature < 733.928 . . . . degrees F
(-35.626, 733.928)
Step-by-step explanation:
It is convenient to let a calculator evaluate the expression for converting °C to °F.
-35.626 < temperature < 733.928 . . . . degrees F
(-35.626, 733.928) . . . . . . . . . . . . . . . . . in interval notation
_____
The given relation is C = 5/9(F -32). The inverse relation is F = 9/5C +32. That is the relation we need to use to answer this question.
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Answer:
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Step-by-step explanation:
1) Collect like terms.
2) Simplify.
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