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3 years ago

I need help with similar triangles

Mathematics

1 answer:

Alika [10]3 years ago

5 0

Answer:

ΔGHI and ΔDEF are similar by SSS criteria

Step-by-step explanation:

Consider triangle GHI and triangle DEF

In ΔGHI, GH = 2, HI =4 and GI = 3.5

In ΔDEF , DE =4, EF = 6 and DF = 7

GH/DE = 2/4 =1/2

HI/EF = 3/6 = 1/2

GI/DF = 3.5/7 = 1/2

The corresponding sides are in same ratio by SSS criteria

ΔGHI and ΔDEF are similar

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L has $200. Ty has 30% more than Lu and twice as much as Ali. How much money do they have altogether? (PLEASE SHOW STEPS!)

saul85 [17]

30% of 200=60 200+60= 260
Ty has £260
£260 x 2= £520

200+260+520= £980

Answer £980

I hope this is right :D

5 0

3 years ago

Measure the lengths of the sides of ∆ABC in GeoGebra, and compute the sine and the cosine of ∠A and ∠B. Verify your calculations

marusya05 [52]

Answer:

$Sin \angle A =0.80$

$Cos \angle A=0.60$

$Sin \angle B =0.60$

$Cos \angle B=0.80$

Step-by-step explanation:

Given

I will answer this question using the attached triangle

Solving (a): Sine and Cosine A

In trigonometry:

$Sin \theta =\frac{Opposite}{Hypotenuse}$ and

$Cos \theta =\frac{Adjacent}{Hypotenuse}$

So:

$Sin \angle A =\frac{BC}{BA}$

Substitute values for BC and BA

$Sin \angle A =\frac{8cm}{10cm}$

$Sin \angle A =\frac{8}{10}$

$Sin \angle A =0.80$

$Cos \angle A=\frac{AC}{BA}$

Substitute values for AC and BA

$Cos \angle A=\frac{6cm}{10cm}$

$Cos \angle A=\frac{6}{10}$

$Cos \angle A=0.60$

Solving (b): Sine and Cosine B

In trigonometry:

$Sin \theta =\frac{Opposite}{Hypotenuse}$ and

$Cos \theta =\frac{Adjacent}{Hypotenuse}$

So:

$Sin \angle B =\frac{AC}{BA}$

Substitute values for AC and BA

$Sin \angle B =\frac{6cm}{10cm}$

$Sin \angle B =\frac{6}{10}$

$Sin \angle B =0.60$

$Cos \angle B=\frac{BC}{BA}$

Substitute values for BC and BA

$Cos \angle B=\frac{8cm}{10cm}$

$Cos \angle B=\frac{8}{10}$

$Cos \angle B=0.80$

Using a calculator:

$A = 53^{\circ}$

So:

$Sin(53^{\circ}) =0.7986$

$Sin(53^{\circ}) =0.80$ -- approximated

$Cos(53^{\circ}) = 0.6018$

$Cos(53^{\circ}) = 0.60$ -- approximated

$B = 37^{\circ}$

So:

$Sin(37^{\circ}) = 0.6018$

$Sin(37^{\circ}) = 0.60$ --- approximated

$Cos(37^{\circ}) = 0.7986$

$Cos(37^{\circ}) = 0.80$ --- approximated

8 0

3 years ago

Read 2 more answers

Mrs. Gomes found that 40% of students at her high school take chemistry. She randomly surveys 12 students. What is the probabili

zlopas [31]

Answer:

The correct answer to the following question will be "0.438".

Step-by-step explanation:

Just because Mrs. Gomes finds around 40% of students in herself high school are studying chemistry.

Although each student becomes independent of one another, we may conclude:

"x" number of the students taking chemistry seems to be binomial to p = constant probability = 0.40

Given:

Number of surveys

= 12

Exactly 4 students have taken chemistry:

$=P(X\leq4)$

$=P(x=0)+P(x=1)+P(x=2)+P(x=3)+P(x=4)$

$=\Sigma_{0}^{4} C_{r}(0.4)^r(0.6)^{12-r}$

On substituting the above equation, we get the probability of approximately "0.438".

So that the above would be the appropriate answer.

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3 years ago

Why does 3^4 x 3^6 simplify to 3^10 instead of 9^10

k0ka [10]

Answer:

3^10

Step-by-step explanation:

Because the rules of index

3^4 = 3*3*3*3

3^6 = 3*3*3*3*3*3

(3^4)(3^6)=

3*3*3*3*3*3*3*3*3*3 = 3^10

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2 years ago

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Benjamin invests $400 in a savings account that earns 5\%5% interest each year. Which expression does not give the correct balan

Phantasy [73]

400(1−0.05) ^3

Step-by-step explanation:

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3 years ago

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