The centre of the rotation is A
The line of the reflection is Y
Vertex A of the triangle ABC when rotated by 90° counterclockwise about the origin,
Rule to be followed,
A(x, y) → P(-y, x)
Therefore, A(1, 1) → P(-1, 1)
Similarly, B(3, 2) → Q(-2, 3)
C(2, 5) → R(-5, 2)
Triangle given in second quadrant will be the triangle PQR.
If the point P of triangle PQR is reflected across a line y = x,
Rule to be followed,
P(x, y) → X(y, x)
P(-1, 1) → X(1, -1)
Similarly, Q(-2, 3) → Y(3, -2)
R(-5, 2) → Z(2, -5)
Therefore, triangle given in the fourth quadrant is triangle XYZ.
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<span>x = 9
Since ZP bisects â OZQ, that means that the measurements for â OZP and â PZQ are the same. So create an equation with their respective values set to each other.
8x - 9 = 5x + 18
Now solve for x
8x - 9 = 5x + 18
Subtract 5x from both sides
3x - 9 = 18
Add 9 to both sides
3x = 27
Divide both sides by 3
x = 9</span>
1)
is simplified into 
2)
is simplified into 
3)
is simplified into 
4)
is simplified into 
5)
is simplified into 
Step-by-step explanation:
We need to solve the polynomials.
1) 
Solving:

So,
is simplified into 
2) 
Solving:

Expanding:

So,
is simplified into 
3) 
Solving:

Expanding:

So,
is simplified into 
4) 
Solving:

Expanding:

SO,
is simplified into 
5) 
Solving:

Expanding:

So,
is simplified into 
Keywords: Solving Polynomials
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Answer:
The surface area of the prism is 
Step-by-step explanation:
we know that
The surface area of the triangular prism is equal to

where
B is the area of the triangular face
P is the perimeter of the triangular face
L is the length of the triangular prism
<em>Find the area of the triangular face B</em>

<em>Find the perimeter of the triangular face P</em>

we have

substitute the values
