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bazaltina [42]
3 years ago
11

PLS HELP!!! I WILL GIVE THE FIRST GOOD ANSWER BRAINLIEST!!!

Mathematics
1 answer:
Nutka1998 [239]3 years ago
8 0

미안 해요 영어를 잘 못해요  sorry I can't help

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2. P337. 23. A large box contains 10,000 ball bearings. A random sample of 120 is chosen. The sample mean diameter is 10 mm, and
Rashid [163]

Answer:

B is True

A, C. D are false

Step-by-step explanation:

Given :

Sample size, n = 120

Mean diameter, m = 10

Standard deviation, s = 0.24

Confidence level, Zcritical ; Z0.05/2 = Z0.025 = 1.96

The confidence interval represents how the true mean value compares to a set of values around the mean computed from a set of sample drawn from the population.

The population here is N = 10000

To obtain

Confidence interval (C. I) :

Mean ± margin of error

Margin of Error = Zcritical * s/sqrt(n)

Margin of Error = 1.96 * 0.24/sqrt(120)

Confidence interval for the 10,000 ball bearing :

10 ± 1.96 * (0.24) / sqrt(120)

Hence. The confidence interval defined as :

10 ± 1.96 * (0.24) / sqrt(120) is the 95% confidence interval for the mean diameter of the 10,000 bearings in the box.

4 0
2 years ago
PLEASE ASAP FOR FULL POINTS
NARA [144]
It’s between B or C
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