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Kazeer [188]
3 years ago
8

The value of 7m−3 is half as big as the value of 12m+1

Mathematics
2 answers:
shutvik [7]3 years ago
6 0
2(7m-3) = 12m+1
14m-6 = 12m+1
2m = 7
m = 7/2
Ksenya-84 [330]3 years ago
4 0

Answer: m = 3\frac{1}{2}

Step-by-step explanation:

the value of 7m−3 is half as big as the value of 12m+1 implies that

7m - 3 = \frac{1}{2} ( 12m + 1)

cross multiplying, we have

2(7m-3) = 12m + 1

Expanding the L.H.S , we have

14m - 6 = 12m + 1

collecting the like terms ,we have

14m - 12m = 1 + 6

2m = 7

Dividing through by 2

m = 7/2

m = 3\frac{1}{2}

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We are given the following in the question:

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As the sample size increases, the standard error that is the sample standard deviation decreases. Thus, quadrupling sample size will half the standard deviation.

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