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Alex73 [517]
2 years ago
12

A study dealing with health care issues plans to take a sample survey of 1500 Americans to estimate the mean dollar amount that

Americans spent on health care this past year.
Identify the population parameter that this study will estimate.
Mathematics
1 answer:
frutty [35]2 years ago
7 0

Answer:

The population parameter of this study is the population mean.

Step-by-step explanation:

A population parameter is a numerical measure representing a certain characteristic of the population. For example, population mean, population variance, population proportion, and so on.

The population parameter is computed using all the values of the population.

The population parameter can be estimated using the sample statistic. If the value of the population parameter is not known, then a random sample of large size, say <em>n</em> ≥ 30 can be selected from the population and the statistic value can be computed. This statistic value is considered as the point estimate of the parameter. It is also known as the unbiased estimator of the parameter.

In this case the survey involved sampling of 1500 Americans to estimate the mean dollar amount that Americans spent on health care in the past year.

The sample selected is used to compute the sample mean dollar amount that Americans spent on health care.

So, the population parameter of this study is the population mean.

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The total monthly profit for a firm is P(x)=6400x−18x^2− (1/3)x^3−40000 dollars, where x is the number of units sold. A maximum
wlad13 [49]

Answer:

Maximum profits are earned when x = 64 that is when 64 units are sold.

Maximum Profit = P(64) = 2,08,490.666667$

Step-by-step explanation:

We are given the following information:P(x) = 6400x - 18x^2 - \frac{x^3}{3} - 40000, where P(x) is the profit function.

We will use double derivative test to find maximum profit.

Differentiating P(x) with respect to x and equating to zero, we get,

\displaystyle\frac{d(P(x))}{dx} = 6400 - 36x - x^2

Equating it to zero we get,

x^2 + 36x - 6400 = 0

We use the quadratic formula to find the values of x:

x = \displaystyle\frac{-b \pm \sqrt{b^2 - 4ac} }{2a}, where a, b and c are coefficients of x^2, x^1 , x^0 respectively.

Putting these value we get x = -100, 64

Now, again differentiating

\displaystyle\frac{d^2(P(x))}{dx^2} = -36 - 2x

At x = 64,  \displaystyle\frac{d^2(P(x))}{dx^2} < 0

Hence, maxima occurs at x = 64.

Therefore, maximum profits are earned when x = 64 that is when 64 units are sold.

Maximum Profit = P(64) = 2,08,490.666667$

6 0
3 years ago
3 folders cost $2.91
WARRIOR [948]

Answer: E. None of the above

Step-by-step explanation:

The equation to solve the problem should look like...2x = $2.91 / 3

3 0
2 years ago
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hram777 [196]

Answer:

Step-by-step explanation:

(1). (8,4)

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5 0
3 years ago
40 POINTS + BRAINLIEST!
kotegsom [21]
Asnwer:
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4 0
2 years ago
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You order plant seeds from a catalog. Each packet cost 0.90 each. The shipping charge is 2.50. If you have 18.50 to spend, how m
kramer
<h2>Answer:</h2>

17

<h2>Step-by-step explanation:</h2>

Cost per Packet * Number of Packets + Shipping =  Amount to Spend

0.90 * b + 2.50 = A

You can spend a maximum of $18.50

A < 18.50

Rearrange the formula to find b

Number of Packets  =  Amount to Spend - Shipping / Cost per Packet

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You can't have 0.7 of a packet so you have to round down to 17.

Now if you put it into the original formula:

0.90 * 17 + 2.50 = 17.80

And 17.80 is less than 18.50.

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