Answer: 2sin^2x+sin2x+cos2x=0 ..... (1).
By using the trigonometric identities below :
sin2x=2sinxcosx
cos2x=cos^2x-sin^2x
We substitute the trigonometric identities into (1).
2sin^2x+2sinxcosx+cos^2x-sin^2x=0
By combining like terms .
sin^2x+2sinxcosx+cos^2x=0.....(2)
The equation (2) is equivalent to the following expression (3).
(sinx+cosx)(sinx+cosx)=0 .....(3).
sinx+cosx=0
cosx=-sinx
divide both sides by cosx
1=-sinx/cosx
-1=sinx/cosx
sinx/cosx=tanx
substitute
-1=tanx
tanx=-1
tangent is negative in 2nd and 4th quadrants
tan135º=-1 (one answer)
tan315º=-1 (second answer)
Step-by-step explanation:
Please refer to the trigonometric identities used and explained above .
7. 233
8. 4
9. 6
10. 5
11. 4
12. 7
13. 7
Answer:
The value of k that makes the relationship shown in the table below proportional is
Step-by-step explanation:
The relation is proportional if
Putting values of x and y to find k.
For x =2 and y =1 k is:
For x =4 and y =2 k is:
For x =6 and y = 3 k is:
For x = 8 and y = 4 k is:
For x =10 and y = 5 k is:
So, The value of k that makes the relationship shown in the table below proportional is
I believe it’s c) complementary
Answer:
C) As x approaches positive infinity, f(x) approaches positive infinity
Step-by-step explanation:
- The domain is NOT all real numbers as x is either smaller than or bigger than 0, and smaller than or bigger than 2. So x ≠ 0 and x ≠ 2.
- This implies that there are asymptotes at x=0 and x=2.
Therefore, the function is NOT continuous.
- The function is NOT increasing over its entire domain as
f(x) = -x² -4x + 1 is decreasing for its given domain of 0<x<2