Answer: 0=0
Step-by-step explanation:
First you want to solve for x
2x+y=−4
Step 1: Add -y to both sides.
2x + y + −y =−4+ −y
2x=−y−4
Step 2: Divide both sides by 2.
2x/2= -y-4/2
x=-1/2y-2
Then you want to plug in your answer for x into the equation so:
2(-1/2y-2)+y=-4
Step 1: Simplify both sides of the equation.
2(-1/2y-2)+y=-4
(2)(
−1/
2
y)+(2)(−2)+y(Distribute)
−y+−4+y=−4
(−y+y)+(−4)=−4(Combine Like Terms)
−4=−4
−4=−4
Step 2: Add 4 to both sides.
−4+4=−4+4
0=0.
Sorry if this wasn't the answer your looking for. If you need more help I suggest using Ma.th.Pa.pa calculator but with out the periods. Hope you have a good day :)
Answer:
Step-by-step explanation:
With a slope of 1 and a y intercept of -3
y = 1x - 3
y = 1(-2) - 3
y = -5
(-2, -5)
Answer:
There are two types of similar triangle problems; these are problems that require you to prove whether a given set of triangles are similar and those that require you to calculate the missing angles and side lengths of similar triangles. Subtract both sides by 130°. Hence; By Angle-Angle (AA) rule, ΔPQR~ΔXYZ.
Step-by-step explanation:
The total weight of candies is unknown. Let x = the total weight of candies.
"One student ate 3/20 of all candies and another 1.2 lb":
The first student ate (3/20)x plus 1.2 lb which is 0.15x + 1.2.
"The second student ate 3/5 of the candies and the remaining 0.3 lb."
The second student ate (3/5)x and 0.3 lb which is 0.6x + 0.3.
Altogether the 2 students ate 0.15x + 1.2 + 0.6x + 0.3.
That was all the amount of candies, so that sum equals x.
0.15x + 1.2 + 0.6x + 0.3 = x
Now we solve the equation for x to find what the total amount of candies was.
0.75x + 1.5 = x
-0.25x = -1.5
x = 6
The total amount of candies was 6 lb.
The first student ate 0.15x + 1.2 = 0.15(6) + 1.2 = 0.9 + 1.2 = 2.1, or 2.1 lb of candies.
The second student ate 0.6x + 0.3 = 0.6(6) + 0.3 = 3.6 + 0.3 = 3.9, or 3.9 lb of candies.
Answer: The first student ate 2.1 lb of candies, and the second student ate 3.9 lb of candies.
Answer:
533.6cm²
Step-by-step explanation:
Hello!
I'm here to answer your question!
<u>Area of each triangular base:</u>
<u />
<u>Area of the rectangular faces:</u>
<u>Add to find the surface area:</u>
Thus, the surface area of the triangular prism is = 533.6 yd²
Hope this helps you!
Hugs from,
Josh
