It’s Debug. definition: “identify and remove errors from (computer hardware or software)”.
Answer:
import java.util.Scanner;
public class ss11{
public static void main (String[]args) {
Scanner keyboard = new Scanner (System.in)
String a1, a2, a3, a4, a5;
int i1, i2, i3, i4, i5;
System.out.println("Enter a four bit binary number:");
a1= keyboard.next();
a2= a1.substring(0,1);
a3= a1.substring(1,2);
a4= a1.substring(2,3);
a5= a1.substring(3,4);
i1 = Integer.parseInt(a2);
i2 = Integer.parseInt(a3);
i3 = Integer.parseInt(a4);
i4 = Integer.parseInt(a5);
i1= i1 * 8;
i2= i1 * 4;
i3= i1 * 2;
i4= i1 * 1;
i5= i1+i2+i3+i4;
System.out.println("The converted decimal number is: +i5);
}
}
Explanation:
Answer:
4. Removing horizontal scroll
Explanation:
Horizontal scroll can be super annoying when you're trying to view someone's web page. It can cut off part of your view and ruin the whole experience. It's best to eliminate horizontal scroll completely wherever you can.
Answer:
O(n) which is a linear space complexity
Explanation:
Space complexity is the amount of memory space needed for a program code to be executed and return results. Space complexity depends on the input space and the auxiliary space used by the algorithm.
The list or array is an integer array of 'n' items, with the memory size 4*n, which is the memory size of an integer multiplied by the number of items in the list. The listSize, i, and arithmeticSum are all integers, the memory space is 4(3) = 12. The return statement passes the content of the arithmetic variable to another variable of space 4.
The total space complexity of the algorithm is "4n + 16" which is a linear space complexity.
