Question

Suppose Charlene Brewster has timesâ (in seconds) of 8.5â, 8.5â, 8.3â, 8.6â, 8.7â, 8.4 and a performance rating of 85â%.

Answer 1

Answer:

1. 10s

2. Slower than normal

Explanation:

1. To calculate the normal time, we first take the average of Charlene's observed times:

Average of Charlene's observed time = $\frac{(8.5+8.5+8.3+8.6+8.7+8.4)}{6}$= 8.5s

Her normal time is therefore: $\frac{Average of Charlene's observed time}{performance rating}$ = $\frac{8.5}{0.85}$ = 10s

2. Since no of Charlene's observed time is higher than normal time of 10s, we can therefore conclude that her work perfomance should be rated as slower than normal.