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8090 [49]
4 years ago
10

Transformation from function

Mathematics
1 answer:
tankabanditka [31]4 years ago
6 0

f(x) = (x - 1)² + 2

g(x) = (x-1)²

f(x) function is a g(x) function that was moved 2 units up, or

g(x) is f(x) that was moved 2 units down.


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2 2/9 is the answer to your question
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Using synthetic division, find (2x4 + 4x3 + 2x2 + 8x + 8) ÷ (x + 2).
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The answer is 32x+8
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5 0
4 years ago
Please help I really need help on this I would really appreciate it anything helps !
andreev551 [17]

Answer:

<em>AXE</em> and <em>CXD  </em>are vertical angles

<em>AXF</em> and <em>FXD  </em>are supplementary angles

<em>DXC </em>and <em>BXC  </em>are complementary angles

<em>EXA</em> and <em>AXB  </em>are adjacent angles

<em>AXC </em>and <em>CXD</em>  are supplementary angles

<em>EXD </em>and <em>AXC </em>are vertical angles

Step-by-step explanation:

6 0
3 years ago
Give an example of a 2x2 matrix without any real eigenvalues:___________
9966 [12]

Answer:

Step-by-step explanation:

An eigenvalue of n × n is a function of a scalar \lambda  considering that there is a solution (i.e. nontrivial) to an eigenvector x of Ax =  

Suppose the matrix A = \left[\begin{array}{cc}-1&-1\\2&1\\ \end{array}\right]

Thus, the equation of the determinant (A - \lambda1) = 0

This implies that:

\left[\begin{array}{cc}-1-\lambda &-1\\2&1- \lambda\\ \end{array}\right] =0

-(1 - \lambda^2 ) + 2 = 0

-1 + \lambda ^2 + 2= 0

\lambda^2 +1 =0

Hence, the eigenvalues of the equation are \mathtt{\lambda = i , -i}

Also, the eigenvalues can be said to be complex numbers.

3 0
3 years ago
. A fruit company recently released a new applesauce. By the end of its first​ year, profits on this product amounted to $24,700
lozanna [386]

Answer:

1) P(x) =14400x+10300 2)y=-4x+19 3)y=\frac{-2x}{3} -14 4) x=-11

(Please check the pictures for better understanding)

Step-by-step explanation:

1) Firstly, let's organize the data. Let the dependent variable x be the years, and the Range P(x) the Profit. So arranging these linear functions y=ax+b and plugging the coordinates for each point (1, 24700) and (4, 67900). Goes:

24,700=x+b

67,900=4x +b

1.1)Solving for b, this Linear System of Equation by the Addition Method goes:

24,700=x+b*(-4)\\67,900=4x+b\\----------\\-98,800=-4x-4b\\67,900=4x+b\\ -----------\\-30900=-3b\\\frac{3b}{3} =\frac{30900}{3}\\ b=10300

1.2) Now, let's find the slope based on those two points (1, 24700) and (4, 67900) and using the formula to find the slope:

m=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}

m=\frac{67900-24700}{4-1}\\ m=\frac{43200}{3}\\ m=14400

So now we can write this Linear Equation for the Profit:

P(x) =14400x+10300

2) An equation of the line perpendicular to 4y=x-8 has a slope equal to m_{2}=-\frac{-1}{m_{1}} the line. In this case, an equation perpendicular to 4y=x-8 .

Rearranging the given equation of the line 4y=x-8 goes:

y=\frac{x}{4} -\frac{8}{4} \\ y=\frac{x}{4}-2

2.1) The slope of this new line is equivalent to m=-4 since -4 is opposite inverse value for the slope of its perpendicular line (1/4).

If the line passes through the point (6,-5), then this point already belongs to this line.

Then, we can write.

-5=-4(6)+b

-5=-24+b

-5+24=-24+24+b

b=19

Now we can write the function:

y=-4x+19

3) Firstly, let's rearrange the equation. Into a General Equation of the Line y=ax+b

2x+3y=5

-2x+2x+3y=5-2x

3y=5-2x

\frac{3y}{3} =\frac{5}{3} -\frac{2x}{3}

y=\frac{-2x}{3}+\frac{5}{3}

3.2) Let's find out b, the linear coefficient by plugging the coordinates of the point (-3,-8).

Also, Parallel lines have the same value for the slope such as m_{1}=m_{2}

-8=-3(-2/3)+b

-8=2+b

-8-2=2-2+b

b=-10

Then the equation of this parallel line is:

y=\frac{-2x}{3} -10

4) Now on this last question, we have to find an equation of the line through the point (-11,-4)  perpendicular to another line y=15

Suppose the slope of the first line is m_{1} and the value of the slope of its perpendicular is m_{2}=\frac{-1}{m_{1}}

y=15 is a horizontal line with slope equals zero, we can rewrite it as y=0x+15.

Then the slope is zero for horizontal lines.

A perpendicular line to a horizontal line is a vertical one.

In addition to this, a vertical line passes through only one point in the x-axis. Then, there is no horizontal variation. This leads the formula of a slope to an undefinition for Real Set.

m=\frac{y_{2}-y_{1}}{0}

The only perpendicular line which passes through the point (-11,-4) to y=15 is the line x=-11.

7 0
3 years ago
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