Mug 2 can hold the most as its volume is greater than that of mug 1
Step-by-step explanation:
To find out which mug holds more let us find the volume of each mug
As we know
Height of first mug =H1= 3 in
Diameter of first mug= D1= 5.5 in
Radius of first mug = R1= ![\frac{5.5}{2}](https://tex.z-dn.net/?f=%5Cfrac%7B5.5%7D%7B2%7D)
= 2.75 in
The volume of first mug M1 is V1
The formula used will be
V=πr2h
V1 will be equal to
![V1=\pi r_{1} 2 h_{1} \\V1= \pi (2.75) (2) (3)\\V1= 51.81](https://tex.z-dn.net/?f=V1%3D%5Cpi%20r_%7B1%7D%20%202%20h_%7B1%7D%20%5C%5CV1%3D%20%5Cpi%20%282.75%29%20%282%29%20%283%29%5C%5CV1%3D%20%2051.81)
V1 = 51.81
Similarly
As we know
Height of second mug = H2= 4 in
Diameter of second mug = D2 = 4.5 in
Radius of second mug = R2= ![\frac{4.5}{2}](https://tex.z-dn.net/?f=%5Cfrac%7B4.5%7D%7B2%7D)
= 2.25 in
The volume of second mug M2 is V2
the formula used will be
V=πr2h
V2 will be equal to
![V2= \pi r_{2} 2h_{2} \\V2 = \pi (2.25)(2)(4)\\V2 = 56.52](https://tex.z-dn.net/?f=V2%3D%20%5Cpi%20r_%7B2%7D%202h_%7B2%7D%20%5C%5CV2%20%3D%20%20%5Cpi%20%282.25%29%282%29%284%29%5C%5CV2%20%3D%2056.52)
V2 = 56.52
So as V2(56.52) is greater than V1(51.81) so mug 2 can hold the most
Keywords: volume of cylinder
Learn more about volume of cylinder at:
#learnwithBrainly
Answer: Answer is D and Yes
Step-by-step explanation:
Divide both sides by a
Bx + c =0
Subtract c from both sides
Bx= —c
Divide both sides by b
And your answer is x= — c/b
Answer: C=250+4s
The reason is because the cost is equal to $250, which is the bus trip, plus $4 additional dollars for each student, s.
Consider the given parallelogram KLMN.
Prove: ![\angle N \cong \angle L, \angle K \cong \angle M](https://tex.z-dn.net/?f=%5Cangle%20N%20%5Ccong%20%5Cangle%20L%2C%20%5Cangle%20K%20%5Ccong%20%5Cangle%20M)
Statement Reason
1.
Definition of parallelogram
2.
Same Side interior angle theorem
![\angle L+ \angle M = 180^\circ](https://tex.z-dn.net/?f=%5Cangle%20L%2B%20%5Cangle%20M%20%3D%20180%5E%5Ccirc)
![\angle K+ \angle L = 180^\circ](https://tex.z-dn.net/?f=%5Cangle%20K%2B%20%5Cangle%20L%20%3D%20180%5E%5Ccirc)
3.
Substitution property
![\angle L+ \angle M=\angle K+ \angle L](https://tex.z-dn.net/?f=%5Cangle%20L%2B%20%5Cangle%20M%3D%5Cangle%20K%2B%20%5Cangle%20L)
4.
Subtraction property of equality
![\angle M = \angle K](https://tex.z-dn.net/?f=%5Cangle%20M%20%3D%20%5Cangle%20K)
Subtraction property of equality tells us that if we subtract some number from one side of an equation, we also must subtract from the other side of the equation to keep the equation the same.
5.
Angle Congruence Postulate
![\angle M \cong \angle K](https://tex.z-dn.net/?f=%5Cangle%20M%20%5Ccong%20%5Cangle%20K)
When two angles are equal, then they are said to be congruent by Angle congruence postulate.