The length of a rectangle is 4 times the width. The rectangle width is 8 m what is the area of the rectangle

Seven balls are randomly withdrawn from an urn that contains 12 red, 16 blue, and 18 green balls. Find the probability that (a)

UNO [17]

Answer:

a) P=0.226

b) P=0.6

c) P=0.0008

d) P=0.74

Step-by-step explanation:

We know that the seven balls are randomly withdrawn from an urn that contains 12 red, 16 blue, and 18 green balls. Therefore, we have 46 balls.

a) We calculate the probability that are 3 red, 2 blue, and 2 green balls.

We calculate the number of possible combinations:

$C_7^{46}=\frac{46!}{7!(46-7)!}=53524680$

We calculate the number of favorable combinations:

$C_3^{12}\cdot C_2^{16}\cdot C_2^{18}=660\cdot 120\cdot 153=12117600$

Therefore, the probability is

$P=\frac{12117600}{53524680}\\\\P=0.226$

b) We calculate the probability that are at least 2 red balls.

We calculate the probability withdrawn of 1 or none of the red balls.

We calculate the number of possible combinations:

$C_7^{46}=\frac{46!}{7!(46-7)!}=53524680$

We calculate the number of favorable combinations: for 1 red balls

$C_1^{12}\cdot C_7^{34}=12\cdot 1344904=16138848$

Therefore, the probability is

$P_1=\frac{16138848}{53524680}\\\\P_1=0.3$

We calculate the number of favorable combinations: for none red balls

$C_7^{34}=5379616$

Therefore, the probability is

$P_0=\frac{5379616}{53524680}\\\\P_0=0.1$

Therefore, the the probability that are at least 2 red balls is

$P=1-P_1-P_0\\\\P=1-0.3-0.1\\\\P=0.6$

c) We calculate the probability that are all withdrawn balls are the same color.

We calculate the number of possible combinations:

$C_7^{46}=\frac{46!}{7!(46-7)!}=53524680$

We calculate the number of favorable combinations:

$C_7^{12}+C_7^{16}+C_7^{18}=792+11440+31824=44056$

Therefore, the probability is

$P=\frac{44056}{53524680}\\\\P=0.0008$

d) We calculate the probability that are either exactly 3 red balls or exactly 3 blue balls are withdrawn.

Let X, event that exactly 3 red balls selected.

$P(X)=\frac{C_3^{12}\cdot C_4^{34}}{53524680}=0.57\\$

Let Y, event that exactly 3 blue balls selected.

$P(Y)=\frac{C_3^{16}\cdot C_4^{30}}{53524680}=0.29\\$

We have

$P(X\cap Y)=\frac{18\cdot C_3^{12} C_3^{16}}{53524680}=0.12$

Therefore, we get

$P(X\cup Y)=P(X)+P(Y)-P(X\cap Y)\\\\P(X\cup Y)=0.57+0.29-0.12\\\\P(X\cup Y)=0.74$

8 0

3 years ago

Please help I don’t know how to set it up

OlgaM077 [116]

Answer:

4a+1s

Step-by-step explanation:

50 divided by 12=4 and a is the variable for albums so 4a

12 x 4 = 48

50-48=$2

Which leaves enough money to buy one song therefore 1s

Hope this helps

Have a great day!

5 0

2 years ago

Read 2 more answers

There are 8 rows in a theater with 12 seats in each row in the middle of the first three rows 4 seats are broken

poizon [28]

There are 84 seats left

7 0

3 years ago

A cube has a volume of greater then 125 cm to the third power. What are the possible lengths of the side of that cube?

e-lub [12.9K]

Volume=legnthn times width times height
a cubes legnth=width=height
therefor
volume=legnth^3
volume is greather than 125
125<legnth^3
cube root both sides
5<legnth
th elegnth is anything greather than 5
an example of some numbers are
6,7,30,3240958049238043284023848239048023843,

6 0

2 years ago

There were 160 people who voted at the town council meeting. Of these people, 30% voted for building a new basketball court in t

tatuchka [14]

Answer:

there are a 112 against

Step-by-step explanation:30% of 160=48 ( 160*0.30=48)

160-48=112

6 0

2 years ago