Solid zinc is added to aqueous cobalt chloride. Using the metal activity series, which chemical equation reflects this reaction
and its outcome? A. 2Zn (s) + 3CoCI2 (aq) —> 2ZnCl2 (aq) + 3Co (s)
B. 2ZnCl2 (aq) + 3Co (s) —> 3CoCI2 (aq) + 2Zn (s)
C. Zn (s) + CoCI2 (aq) —> ZnCl2 (aq) + Co (s)
D. Zn (s) + CoCI2 (aq) —> NR
The activity series of metals gives a clearer understanding of how metals displaces other metals in solution. Metals higher in the activity series will always displace those lower in the activity series.
Zinc, Zn is higher in the activity series than cobalt, Co. Therefore, zinc, Zn will displace cobalt, Co in any solution.
Considering the options given above, only option C. reflect the reaction and it is also balanced.
Considering the reaction stoichiometry and Avogadro's Number, the mass of barium chloride produced is 21.6 grams.
<h2>Balanced reaction</h2>
The balanced reaction is
2 HCl + Ba → BaCl₂ + H₂
<h2>Moles of HCl that react</h2>
Avogadro's Number is called the number of particles that make up a substance (usually atoms or molecules) and that can be found in the amount of one mole of said substance. Its value is 6.023×10²³ particles per mole. Avogadro's number applies to any substance.
Then you can apply the following rule of three: if 6.023×10²³ molecules are contained in 1 mole of HCl, then 1.25×10²³ molecules are contained in how many moles of HCl?
amount of moles of HCl= (1.25×10²³ molecules × 1 mole)÷ 6.023×10²³ atoms
<u><em>amount of moles of HCl= 0.2075 moles</em></u>
Then, 0.2075 moles of HCl react.
<h2>Reaction stoichiometry</h2>
By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:
HCl: 2 moles
Ba: 1 mole
BaCl₂: 1 mole
H₂: 1 mole
<h2>Mass of barium chloride produced</h2>
Then you can apply the following rule of three: if by stoichiometry 2 moles of HCl produce 1 mole of BaCl₂, 0.2075 moles of HCl will produce how many moles of BaCl₂?
<u><em>amount of moles of BaCl₂= 0.10375 moles</em></u>
Being the molar mass of BaCl₂ 208.24 g/mole, then the mass of barium chloride produced is calculated as:
Finally, the mass of barium chloride produced is 21.6 grams.