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8_murik_8 [283]
3 years ago
10

What is the name of molecule?

Chemistry
1 answer:
luda_lava [24]3 years ago
7 0

Answer:

functional group - carboxylic

molecule name- propanic acid

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How many neutrons are found in a stable isotope of uranium-235?
bezimeni [28]

thx but it's actually 143

8 0
3 years ago
Calculate the change in entropy if Br2(l) is converted to Br2(g).
Alik [6]

Ans: The entropy change for the given reaction is 93.3 J/K

Given reaction:

Br2(l) → Br2(g)

ΔS = ∑n(products)S⁰(products) - ∑n(reactants)S⁰(reactants)

     = 1 mole* S°(Br2(g)) - 1 mole*S°(Br2(l))

     =  1 mole *245.5 J/mol-K - 1 mole*152.2 J/mol-K

     = 93.3 J/K

5 0
3 years ago
Convert 7.34 miles into meters (1mile = 1.6 Km)
Lera25 [3.4K]

Answer:

11812.58 meters = 11.81258 Km

Explanation:

hope that helps

8 0
3 years ago
Elemental iodine (I 2) is a solid at room temperature. What is the major attractive force that exists among different I 2 molecu
Ulleksa [173]

Explanation:

As I_{2} is a covalent compound because it is made up by the combination of two non-metal atoms. Atomic number of an iodine atom is 53 and it contains 7 valence electrons as it belongs to group 17 of the periodic table.

Therefore, sharing of electrons will take place when two iodine atoms chemically combine with each other leading to the formation of a covalent bonding.

Hence, weak forces like london dispersion forces will be present between a molecule of I_{2}.

The weak intermolecular forces which can arise either between nucleus and electrons or between electron-electron are known as dispersion forces. These forces are also known as London dispersion forces and these are temporary in nature.

thus, we can conclude that london dispersion force is the major attractive force that exists among different I_{2} molecules in the solid.

7 0
3 years ago
Determine the freezing point of a 0.51 molal
Elan Coil [88]

Answer:

-65.897°C.

Explanation:

  • Adding solute to water causes depression of the boiling point.
  • The depression in freezing point (ΔTf) can be calculated using the relation: <em>ΔTf = Kf.m,</em>

where, ΔTf is the depression in freezing point of chloroform solution.

Kf is the molal depression constant of chloroform (Kf = 4.70°C.kg/mol).

m is the molality of the solution (m = 0.51 m).

∴ ΔTf = Kf.m = (4.70°C.kg/mol)(0.51 m) = 2.397°C.

∴ The freezing point of the solution = (freezing point of chloroform) - ΔTf = (-63.5°C) - (2.397°C) = -65.897°C.

7 0
3 years ago
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