Subatomic particles include electrons, the negatively charged, almost massless particles that nevertheless account for most of the size of the atom, and they include the heavier building blocks of the small but very dense nucleus of the atom, the positively charged protons and the electrically neutral neutrons.
And I don't see any of the particles. so I can only answer the first one.
Your general impression suggests that your immediate action should be to call for additional help. The correct option is a.
<h3>What is immediate action?</h3>
Immediate actions are the actions that are taken without taking any time. These actions are taken when there is no time to think, and you should immediately think about the actions. The emergency condition needs immediate help.
During the time of general impression, one should immediately call for additional help. Additional people will give you suggestions for the problem.
Thus, the correct option is a. call for additional help.
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Answer:
C.) 3.5 atm
Explanation:
Because you are dealing with pressure and volume, you can use Boyle's Law to help you find the missing variable. The general formula looks like this:
P₁V₁ = P₂V₂
In this formula, "P₁" and "V₁" represent the pressure and volume of the chamber originally. "P₂" and "V₂" represent the final pressure and volume. You have been given the values of all the other variables but "P₂". Therefore, you can plug these values into the formula and simplify to find the final pressure.
P₁ = 1.5 atm
V₁ = 1.4 L
P₂ = ?
V₂ = 0.60 L
P₁V₁ = P₂V₂ <---- Boyle's Law formula
(1.5 atm)(1.4 L) = P₂(0.60 L) <---- Plug in values
2.1 = P₂(0.60 L) <---- Multiply 1.5 and 1.4
3.5 = P₂ <----- Divide both sides by 0.60
From the gas law, PV=nRT we can say that P(pressure), V(volume) and T (temperature) are related to each other. The initial volume of sample is 408 ml
Given that initial volume of the sample = V1
initial pressure of the sample = 0.92atm
initial temperature of the sample = 23.2oC
Final pressure of the sample = 1.3atm
Final temperature of the sample = 40.1 oC
Final volume of the sample = 500ml = 0.5L
Using the relation P1V1/T1 = P2V2/T2
V1 = 1.3x0.5x23.2/40.1x0.92 = 15.08/36.892 = 0.408
Hence the initial volume of sample = 408 ml
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