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irinina [24]
3 years ago
14

Six cards numbered from 1 to 6 are placed in an empty bowl. First one card is drawn and then put back into the bowl; then a seco

nd card is drawn. If the cards are drawn at random and if the sum of the numbers on the cards is 8, what is the probability that one of the two cards drawn is numbered 5 ?
Mathematics
1 answer:
tangare [24]3 years ago
7 0

Answer:

Step-by-step explanation:

Given that Six cards numbered from 1 to 6 are placed in an empty bowl. First one card is drawn and then put back into the bowl; then a second card is drawn. If the cards are drawn at random

Since with replacement, repitition of numbers is possible

Possible drawings to give sum of 8 is

(2,6) (6,2) (3,5)(5,3)(4,4)

Out of this favourable events with 5 = (3,5) (5,3)

Hence required probability = \frac{2}{5} =0.4

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tia_tia [17]

Answer:

2

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Step-by-step explanation:

We are given 2 fractional numbers:

1.\ \dfrac{2}4\\2.\ \dfrac{5}8

We have to use fraction strips to compare to the fractional numbers.

Let we are Comparing \frac{2}{4} with the length of x number of \frac{1}4 sections.

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i.e.

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Now, let us have a look at 3rd part of question:

The sections of 2/4 is _____ the length of 5/8. Therefore, 2/4 < 5/8

Let the answer be z.

So, the equation becomes:

\dfrac{2}{4} = z \times \dfrac{5}{8}\\\Rightarrow z = \dfrac{2 \times 8}{4 \times 5}\\\Rightarrow z = \dfrac{2 \times 2}{5}\\\Rightarrow z = \dfrac{4}{5}

So, the answers are:

2

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\dfrac{4}{5}

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