The acceleraton of the spaceship is 20 m/s^2. Thank you for posting your question here at brainly. I hope the answer will help you. Feel free to ask more questions.
Answer:
D
Explanation:
The gravitational force between any two objects is affected by the masses of the objects and the distance between them. The greater the masses of the objects are, the stronger the gravitational force is.
Since all four of the satellites are the same distance from the Earth's surface, only their masses affect the strength of the gravitational force. At 903 kilograms, satellite D has the greatest mass, so the gravitational force pulling it toward the Earth is the greatest.
Answer:
q = 4.04×10^-12C
n = 2.53×10^7
Explanation:
1. Electrostatic force on charge due to electrical field E is F = qE
Gravitational force due to weight of drop of mass M is F = mg, when net force is zero we have to find the charges on the drop.
2. Charge on drop: since gravitational force is acting downward, electric field is acting upward and we equate both equations.
Therefore, Fg = Fe
qe = mg
q = mg/E
q = 3.50×10^-9kg×9.8m/s²/8480N/c
q = 4.04 × 10^-12
3. Number of protons by quantitization law
n = q/e
n = 4.04× 10^-12/8480
n = 2.53× 10^7
Answer:
5541Hz
Explanation:
If the frequency of a wave is directly proportional to the velocity we have;
F = kV where;
F is the frequency
K is the constant of proportionality
V is the velocity
Since f = kV
K = f/v
K = F1/V1 = F2/V2
Given f1 = 412Hz v1 = 25.8m/s f2 = ? V2 = 347m/s
Substituting in the formula we have;
412/25.8=f2/347
Cross multiplying
25.8f2 = 412×347
F2 = 412×347/25.8
F2 = 5541Hz
The frequency heard will be 5541Hz
Efficiency =Velocity Ratio/Mechanical Advantage *100%
80%=6/MA*100%
Therefore MA=7.5
MA=Load/Effort
7.5=300/E
E=300/7.5
E=40