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Dafna1 [17]
3 years ago
10

I need help with a conservation of energy question, 1. b) on the attachment :)

Physics
1 answer:
rosijanka [135]3 years ago
4 0

Explanation:

Dina tiktokneed help with a conservation of energy question, 1. b) on the attachment :)

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a_sh-v [17]

Answer:

"humans cannot hear all the same sound frequencies as animals", & "Humans cannot make make all the same sound frequencies as animals" are correct. the other two are incorrect, hope this helps!

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3 years ago
Read 2 more answers
A girl launches a toy rocket from the ground. The engine experiences an average thrust of 5.26 N. The mass of the engine plus fu
Triss [41]

Answer: The answer for A is - v = 786.93 m/s

The answer for B is - v = 122.40 m/s

Explanation:

a) To find the average exhaust speed (v) of the engine we can use the following equation:

F = vΔm

Where:

F: is the thrust by the engine = 5.26 N

Δm: is the mass of the fuel = 12.7 g

Δt: is the time of the burning of fuel = 1.90 s

v = F×ΔT/ΔT

b) To calculate the final velocity of the rocket we need to find the acceleration.

The acceleration (a) can be calculated as follows:

a = F/M

In the above equation, m is an average between the mass of the engine plus the rocket case mass and the mass of the engine plus the rocket case minus the fuel mass:

m = (m_{engine} + m_{rocket}) + (m_{engine} + m_{rocket} - m_{fuel})}{2} = {2*m_{engine} + 2*m_{rocket} - m_{fuel}}{2} = 2*25.0 g + 2*63.0 g - 12.7 g}{2} = 81.65 g

Now, the acceleration is:

a = 5.26 N/81.65-t 10^³kg} = 64.42 m*s^²

Finally, the final velocity of the rocket can be calculated using the following kinematic equation:

v= v_{0} + at = 0 + 64.42 m*s^{-2}*1.90 s = 122.40 m/s

7 0
3 years ago
16g 2g/cm3 what is the Volume
lord [1]

Answer:

V =  1.25E-7 cubic meter

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3 years ago
A bowling ball rolls off the edge of a cliff, moving horizontally at 20 m/s. I have to plot the position of the bowling ball on
liubo4ka [24]
For counting x you use simple equation for the distance covered by the object when it moves with constant velocity:
s=v*t
that gives you 20m after 1st second, 40 m after 2nd second, 60 m after 3rd second and so on.

For counting y you have to use the equation for the distanced covered by the object moving with constantly accelerating velocity (symbols refering to vertical movement):
h=g\frac{t^{2}}{2}
that gives you 5m after 1st second, 20m afters 2nd second, 45m after 3rd second and so on.
Add minus signs before y positions to receive graph presenting the movement of the ball.
So the points are: P1=[20,-5], P2=[40,-20], P3=[60,-45] and so on... Pn=[x,y].
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3 years ago
I need help with the circled one
Whitepunk [10]
Yes the answer is yes 
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