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Alborosie
3 years ago
5

The maximum value of the electric field in an electromagnetic wave is 2.0 V/m. What is the maximum value of the magnetic field i

n that wave
Physics
1 answer:
Eddi Din [679]3 years ago
7 0

Answer:

The maximum value of the magnetic field in the given wave is 6.67 nT.

Explanation:

Given;

maximum value of the electric field, E₀ = 2.0 V/m

The maximum value of the magnetic field in the given wave is calculated as;

B_o = \frac{E_o}{c}

where;

c is the speed of light = 3 x 10⁸ m/s

B_o = \frac{E_o}{c} \\\\B_o = \frac{2}{3 \ \times \ 10^8} \\\\B_o = 6.67 \ \times \ 10^{-9} \ T\\\\B_o = 6.67 \ nT

Therefore, the maximum value of the magnetic field in the given wave is 6.67 nT.

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What is the efficiency of a device that takes 400J of heat and does 120J of work while giving off 280 J of heat
zubka84 [21]

Answer:

30%

Explanation:

Efficiency = useful work / heat absorbed x 100

= 120/400 x 100

= 0.3 x 100

= 30%

6 0
3 years ago
If the radius of a star increases by a factor of 6 the surface area of the star increases how many times?
Dennis_Churaev [7]

Answer:

When radius of star increase by 6 factor then area of star will increase by a factor of 36.

Explanation:

As we know that

Area of star A given as

A=4\pi R^2

Where R is the radius of star.

Area of star when radius become 6 times

A'=4\pi (6R)^2

A'=4\pi \times 36\times R^2

So

A'=36A

We can say that when radius of star increase by 6 factor then area of star will increase by a factor of 36.

8 0
3 years ago
An ideal gas is enclosed in a piston, and 1600 J of work is done on the gas. As this happens, the internal energy of the gas inc
Phantasy [73]

Answer:

- 1100 J heat flows out

Explanation:

dW = - 1600 J (as work is done on the gas)

dU = 500 J

dQ = ?

According to the first law of thermodynamics

dQ = dU + dW

dQ = 500 - 1600

dQ = - 1100 J

As heat is negative so it flows out.

3 0
3 years ago
Can you access an instance variable from a static method? explain why or why not.
marusya05 [52]
<span>The reason a static method can't access instance variable is because static references the class not a specific instance of the class so there is no instance variable to access.</span>
5 0
4 years ago
Calculate the first and second velocities of the car with four washers attached to the pulley, using the formulas v1 = 0. 25 m /
castortr0y [4]

The first and second velocities of the car are 0.25/t1 and 0.50/t2 respectively.

Given data:

The value of the first distance is, d1 = 0.25 m.

The value of the second distance is, d2 = 0.50 m.

The ratio of distance covered by an object in a specific direction and the time taken to cover the distance is known as the velocity of the object. Mathematically, the expression for the velocity is,

v = d/t

Here,

d is the distance covered.

t is the average time taken to cover the distance.

Then the first velocity of the car at 0.25 m is,

v1 = d1/t1

v1 = 0.25 / t1

here, t1 is the average time for first distance.

And the second velocity of the car with four washers at the 0. 50 m mark is,

v2 = d2/t2

v2 = 0.50 /t2

here, t2 is the average time for the second distance.

Thus, we can conclude that the first and second velocities of the car are 0.25/t1 and 0.50/t2 respectively.

Learn more about the velocity here:

brainly.com/question/862972

6 0
2 years ago
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