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Katyanochek1 [597]
3 years ago
6

The first three terms of a sequence are given. Round to the nearest thousandth (if

Mathematics
1 answer:
notka56 [123]3 years ago
8 0

Answer:

Step-by-step explanation:

3,5,6,

a =3

d = 5-3 = 2

Tn= a+(n-1)d

T6= 3+(6-1)2 = 3 + (5)2 = 3 + 10 = 13

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Find the sum of each series, if it exists<br>91 + 85 + 79 + … + (­29)
Natali [406]

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Step-by-step explanation:

Note: In the given series it should be -29 instead of 29 because 29 cannot be a term of AP whose first term is 91 and common difference is -6.

Consider the given series is

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nth term of an AP is

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