The midpoint of the diameter endpoints is the center of the circle...
((2+9)/2, (4+4)/2)
(5.5, 4) is the center of the circle...
The distance between the two endpoints is the diameter of the circle...
d^2=(4-4)^2+(9-2)^2
d^2=0+49
d^2=49
d=7
So the radius is d/2 which is 3.5
Now the equation of a circle is:
(x-h)^2+(y-k)^2=r^2 where (h,k) is the coordinates of the center and r is the radius.
Earlier we found (h,k) to be (5.5, 4) and r=3.5 so our equation is:
(x-5.5)^2+(y-4)^2=3.5^2
(x-5.5)^2+(y-4)^2=12.25
C/20 cups flour in one cake is the term.
Step-by-step instructions: * First, let's go over how to solve the problem: - There are ten students; each produced two chocolate cakes; they all used the same recipe; the total amount of flour used is C cups * Let's put this information into an equation: There are ten pupils, and each of them produced two cakes. The total number of cakes is ten plus two, for a total of twenty cakes
It would be 24 total windows and 20 windows without leaks. You could possible write it as 24:20 or 24 to 20 or 24/20.
<span>We could use 7+7=14 to find the sum of 6+7.
<u><em>Explanation</em></u><span><u><em>: </em></u>
7+7=14 is one of the two closest doubles to 6+7.
We know that:
7 is 1 more than 6; this means:
7+7 will be 1 more than 6+7.
7+7=14, so finding 1 less,
6+7=13.</span></span>
How can you justify that YZ is congruent to RM?
Your answer will be: (The first option) CPCTC
Which statement cannot be justified given that triangle PBJ is congruent to triangle TIM?
Your answer will be: (The last option) segment JP congruent to segment MI
Which theorem or postulate can you use to prove triangle ADM congruent to triangle ZMD?
Your answer will be (The third option) SAS
