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joja [24]
3 years ago
8

Your neighbor’s 14-month-old toddler says things like "cup!" when he means that he would like a cup of milk. Your neighbor think

s that his toddler is very lazy. What is happening? The toddler is __________. cognitively impaired using holophrases, which is developmentally appropriate language-delayed and needs professional assistance trying to manipulate his father and needs to be disciplined
Physics
1 answer:
Serhud [2]3 years ago
6 0

Answer:

The options are not properly punctuated.  

(a) cognitively impaired (b) using holophrases which is developmentally appropriate  (c) language-delayed and needs professional assistance (d)  trying to manipulate his father and needs to be disciplined

The correct answer is  (b) using holophrases which is developmentally appropriate

Explanation:

Holophrases are one of the single-word utterances characteristic of children in the early stages of language acquisition,   it is the use of a single word to express a complex idea. Holophrases are normal among toddlers within the  age of two years  below.

Hence the the use of "cup" by the toddler to express his intent for a cup of milk is referred to as holophrases which is developmentally appropriate

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. Consider the equation =0+0+02/2+03/6+04/24+5/120, where s is a length and t is a time. What are the dimensions and SI units of
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Answer:

See Explanation

Explanation:

Given

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Solving (a): Units and dimension of s_0

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Hence:

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Solving (b): Units and dimension of v_0

Remove the other terms of the equation, we have:

s=v_0t

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v_0t = s

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Replace s and t with their units

v_0 = \frac{L}{T}

v_0 = LT^{-1}

Hence:

v_0 \to LT^{-1} --- dimension

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Solving (c): Units and dimension of a_0

Remove the other terms of the equation, we have:

s=\frac{a_0t^2}{2}

Rewrite as:

\frac{a_0t^2}{2} = s_0

Make a_0 the subject

a_0 = \frac{2s_0}{t^2}

Replace s and t with their units [ignore all constants]

a_0 = \frac{L}{T^2}\\

a_0 = LT^{-2

Hence:

a_0 = LT^{-2 --- dimension

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Solving (d): Units and dimension of j_0

Remove the other terms of the equation, we have:

s=\frac{j_0t^3}{6}

Rewrite as:

\frac{j_0t^3}{6} = s

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j_0 = \frac{6s}{t^3}

Replace s and t with their units [Ignore all constants]

j_0 = \frac{L}{T^3}

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Remove the other terms of the equation, we have:

s=\frac{S_0t^4}{24}

Rewrite as:

\frac{S_0t^4}{24} = s

Make S_0 the subject

S_0 = \frac{24s}{t^4}

Replace s and t with their units [ignore all constants]

S_0 = \frac{L}{T^4}

S_0 = LT^{-4

Hence:

S_0 = LT^{-4 --- dimension

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Ignore other terms of the equation, we have:

s=\frac{ct^5}{120}

Rewrite as:

\frac{ct^5}{120} = s

Make c the subject

c = \frac{120s}{t^5}

Replace s and t with their units [Ignore all constants]

c = \frac{L}{T^5}

c = LT^{-5}

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c \to LT^{-5} --- dimension

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