Answer:
The gravitational force on the elevator = 4500N
Explanation:
The given parameters are;
The force applied by the elevator, F = 4500 N
The acceleration of the elevator = Not accelerating
From Newton's third law of motion, the action of the cable force is equal to the reaction of the gravitational force on the elevator which is the weight, W and motion of the elevator as follows;
F = W + Mass of elevator × Acceleration of elevator
∴ F = W + Mass of elevator × 0 = W
F = 4500 N = W
The net force on the elevator is F - W = 0
The gravitational force on the elevator = W = 4500N.
Answer:
![1.475\times 10^{-13}\ C/m^3](https://tex.z-dn.net/?f=1.475%5Ctimes%2010%5E%7B-13%7D%5C%20C%2Fm%5E3)
Explanation:
= Permittivity of free space = ![8.85\times 10^{-12}\ F/m](https://tex.z-dn.net/?f=8.85%5Ctimes%2010%5E%7B-12%7D%5C%20F%2Fm)
A = Area
h = Altitude = 600 m
Electric flux through the top would be
(negative as the electric field is going into the volume)
At the bottom
![120A](https://tex.z-dn.net/?f=120A)
Total flux through the volume
![\phi=120-110\\\Rightarrow \phi=10A](https://tex.z-dn.net/?f=%5Cphi%3D120-110%5C%5C%5CRightarrow%20%5Cphi%3D10A)
Electric flux is given by
![\phi=\dfrac{q}{\epsilon_0}\\\Rightarrow q=\phi\epsilon_0\\\Rightarrow q=10A\epsilon_0](https://tex.z-dn.net/?f=%5Cphi%3D%5Cdfrac%7Bq%7D%7B%5Cepsilon_0%7D%5C%5C%5CRightarrow%20q%3D%5Cphi%5Cepsilon_0%5C%5C%5CRightarrow%20q%3D10A%5Cepsilon_0)
Charge per volume is given by
![\rho=\dfrac{q}{v}\\\Rightarrow \rho=\dfrac{10A\epsilon_0}{Ah}\\\Rightarrow \rho=dfrac{10\epsilon_0}{h}\\\Rightarrow \rho=\dfrac{10\times 8.85\times 10^{-12}}{600}\\\Rightarrow \rho=1.475\times 10^{-13}\ C/m^3](https://tex.z-dn.net/?f=%5Crho%3D%5Cdfrac%7Bq%7D%7Bv%7D%5C%5C%5CRightarrow%20%5Crho%3D%5Cdfrac%7B10A%5Cepsilon_0%7D%7BAh%7D%5C%5C%5CRightarrow%20%5Crho%3Ddfrac%7B10%5Cepsilon_0%7D%7Bh%7D%5C%5C%5CRightarrow%20%5Crho%3D%5Cdfrac%7B10%5Ctimes%208.85%5Ctimes%2010%5E%7B-12%7D%7D%7B600%7D%5C%5C%5CRightarrow%20%5Crho%3D1.475%5Ctimes%2010%5E%7B-13%7D%5C%20C%2Fm%5E3)
The volume charge density is ![1.475\times 10^{-13}\ C/m^3](https://tex.z-dn.net/?f=1.475%5Ctimes%2010%5E%7B-13%7D%5C%20C%2Fm%5E3)
Answer:
earth's shadow covering the moon,thats lunar eclipse
Answer:B 20 newtons opposite to the direction of the applied force
Explanation:
Ke= 1/2 x m x v^2
Ke= 1/2 x 2.1 x 30^2
Energy = 945 J