Answer:
100,048
Explanation:
K.E = 1/2 m (v)^2
K.E = 1^/2 * 74 * (52)^2
K.E = 100,048J =100.048kJ
The power developed is 500 W ( to the nearest Watt)
Power(P) is the rate at which work is done. Work done (W) is the product of the force applied on the object and the displacement (s) made by the point of application of the force.


Therefore,

Substitute the given values of force , displacement and time


Thus the Power can be rounded off to the nearest value of 500 W
Answer:
a) 
b) 
c) 
d)
or 18.3 cm
Explanation:
For this case we have the following system with the forces on the figure attached.
We know that the spring compresses a total distance of x=0.10 m
Part a
The gravitational force is defined as mg so on this case the work donde by the gravity is:

Part b
For this case first we can convert the spring constant to N/m like this:

And the work donde by the spring on this case is given by:

Part c
We can assume that the initial velocity for the block is Vi and is at rest from the end of the movement. If we use balance of energy we got:

And if we solve for the initial velocity we got:

Part d
Let d1 represent the new maximum distance, in order to find it we know that :

And replacing we got:

And we can put the terms like this:

If we multiply all the equation by 2 we got:

Now we can replace the values and we got:


And solving the quadratic equation we got that the solution for
or 18.3 cm because the negative solution not make sense.
Responder:
Fy = 2474,8737
Fx = 2474,8737
Explicación:
Dado que :
Dado:
Fuerza, F = 3500 N
Ángulo formado con la horizontal, θ, = 45 °
Los componentes de una fuerza se pueden descomponer en componentes verticales y horizontales.
El componente vertical Fy; y
El componente horizontal Fx
Fy = Fuerza * sinθ
Fy = 3500 * sin45 °
Fy = 2474,8737
El componente horizontal:
Fx = Fuerza * cosθ
Fy = 3500 * cos45 °
Fy = 2474,8737