All categories

3 years ago

Please help me with solving worded quadratic equations

Mathematics

1 answer:

Lilit [14]3 years ago

8 0

1. we know that product (x) so divide it by 2 and then minus some from 1 side and add on to the other side

You might be interested in

Which of the following is the graph of y = 5?

Annette [7]

Slope: 0
Y-intercept: 5
The answer is 0,5
I hope this helps.

8 0

3 years ago

Please help! It's a final!!

Svetach [21]

Answer:

BBBBBBBBBB

Step-by-step explanation:

yeah if you add 2 without parenthesis it goes up

6 0

3 years ago

Consider the following sequence

wlad13 [49]

Answer:

a₇ = 2.375

Step-by-step explanation:

There is a common ratio r between consecutive terms, that is

r = $\frac{-76}{152}$ = $\frac{38}{-76}$ = $\frac{-19}{38}$ = - $\frac{1}{2}$

This indicates the sequence is geometric with nth term

$a_{n}$ = a₁ $(r)^{n-1}$

where a₁ is the first term and r the common ratio

Here a₁ = 152 and r = - $\frac{1}{2}$ , then

$a_{n}$ = 152 $(-\frac{1}{2}) ^{n-1}$ , so

a₇ = 152 $(-\frac{1}{2}) ^{6}$ = 152 × $\frac{1}{64}$ = 2.375

3 0

3 years ago

Read 2 more answers

After earning interest, the balance of an account is $420. The new balance is 7/6 of the original balance. Write an equation tha

vredina [299]

<h3>Given</h3>

The current balance is $420.

The current balance is 7/6 of the original balance, b

equation to use to find b

<h3>Solution</h3>

Equate the two descriptions of the current balance.

... $420 = (7/6)b . . . . . equation to use to find b

3 0

3 years ago

PLEASE, I NEED HELP FOR A CLASS. The length of triangle base is 26. A line, which is parallel to the base divides the triangle i

sasho [114]

Answer:

$DE=18.38$

Step-by-step explanation:

It is given that the length of triangle base is 26 that is BC=26.

A line, which is parallel to the base divides the triangle into two equal area parts.

Therefore, from the given information, $\frac{{\triangle}ADE}{ar ABC}=\frac{1}{2}$ .

Now, since it is given that A line, which is parallel to the base divides the triangle into two equal area parts, thus

$\frac{ar ADE}{arABC}=\frac{1}{2}=\frac{(DE)^{2}}{(BC)^{2}}$

⇒ $\frac{(DE)^{2}}{(BC)^{2}}=\frac{1}{2}$

⇒ $\frac{(DE)^{2}}{(26)^{2}}=\frac{1}{2}$

⇒ $(DE)^{2}=13{\times}26=338$

⇒ $DE=18.38$

7 0

3 years ago