Answer:
∠ EFH = 112°
Step-by-step explanation:
∠ ACD and ∠ EFH are Alternate exterior angles and are congruent, thus
11x - 20 = 9x + 4 ( subtract 9x from both sides )
2x - 20 = 4 ( add 20 to both sides )
2x = 24 ( divide both sides by 2 )
x = 12
Thus
∠ EFH = 11x - 20 = 11(12) - 20 = 132 - 20 = 112°
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Answer:
1.) mean
2.) H0 : μ = 64
3.) 0.0028
4) Yes
Step-by-step explanation:
Null hypothesis ; H0 : μ = 64
Alternative hypothesis ; H1 : μ < 64
From the data Given :
70; 45; 55; 60; 65; 55; 55; 60; 50; 55
Using calculator :
Xbar = 57
Sample size, n = 10
Standard deviation, s = 7.14
Test statistic :
(xbar - μ) ÷ s/sqrt(n)
(57 - 64) ÷ 8 / sqrt(10)
Test statistic = - 2.77
Pvalue = (Z < - 2.77) = 0.0028 ( Z probability calculator)
α = 10% = 0.1
Reject H0 ; if P < α
Here,
P < α ; Hence, we reject the null
150+3p
p=30
150+3(30)
150+90
240
When p=30 in 150+3p, the final value is 240.
The solution as in where do they intersect? if so, it would be 0.0769 and -0.0769