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3 years ago

Danny writes this sentence:

Mathematics

2 answers:

Cloud [144]3 years ago

8 0

5x-3=12: The equation

aliina [53]3 years ago

5 0

Lets first figure out what each of the words mean in symbols.

Three less: - 3
a number: x (you can use any variable, but the question says to use x)
five times a number: 5x
is 12: = 12

Now we need to put the equation together.

5x - 3 = 12 is the sequence that Danny wrote.

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Hector has a floor plan showing his new house. On the floor plan, his bedroom is 3 inches wide and 3

Nat2105 [25]

Question:

Hector has a floor plan showing his new house. On the floor plan, his bedroom is 3 inches wide and 3 1/2 inches long. The scale of the floor plan is 1/4 inch = 1 foot. What is the actual length of Hector’s room?

Answer:

The actual length of Hector room is 14 foot

Solution:

Given that, On the floor plan, his bedroom is 3 inches wide and $3\frac{1}{2}$ inches long

The scale of floor plan is given as:

$\frac{1}{4} \text{ inch} = 1 \text{ foot }$

Therefore,

$1 \text{ inch } = 4 \text{ foot}$

To find: Actual length of floor

From given question,

$length = 3\frac{1}{2} \text{ inches}$

Converting the mixed fraction to improper fraction,

$length = \frac{2 \times 3 + 1}{2} = \frac{7}{2} \text{ inches }$

Since, 1 inch = 4 foot

$\frac{7}{2} \text{ inches } = \frac{7}{2} \times 4 \text{ foot } = 14 \text{ foot }$

Thus actual length of Hector room is 14 foot

6 0

2 years ago

2y = 4x - 8 3x + 2y = 6 graph

Vinvika [58]

Answer:

see attached

Step-by-step explanation:

I find it convenient to let a graphing calculator draw the graph (attached).

If you're drawing the graph by hand, there are a couple of strategies that can be useful.

The first equation is almost in slope-intercept form. Dividing it by 2 will put it in that form:

y = 2x -4

This tells you that the y-intercept, (0, -4) is a point on the graph, as is the point that is up 2 and right 1 from there: (1, -2). A line through those points completes the graph.

The second equation is in standard form, so the x- and y-intercepts are easily found. One way to do that is to divide by the constant on the right to get ...

x/2 +y/3 = 1

The denominators of the x-term and the y-term are the x-intercept and the y-intercept, respectively. If that is too mind-bending, you can simply set x=0 to find the y-intercept:

0 +2y = 6

y = 6/2 = 3

and set y=0 to find the x-intercept

3x +0 = 6

x = 6/3 = 2

Plot the intercepts and draw the line through them for the graph of this equation.

___

Here, we have suggested graphing strategies that don't involve a lot of manipulation of the equations. The idea is to get there as quickly as possible with a minimum of mistakes.

8 0

3 years ago

Can someone help pls.

kap26 [50]

My goodness, this is rather confusing in the way it is worded. Nevertheless, I will attempt to do what I can. Just please keep in mind that this is my own interpretation of the problem, and therefore could be... incorrect.

I think, to start out, we could set up the problem like so

15 + t ≥ 26

because t is not a set number.

Then all that is needed is to subtract 15 from both sides, and the equation becomes

t ≥ 11

So the resulting answer is t ≥ 11.

I hope that my interpretation helps.

-Toremi

8 0

2 years ago

Read 2 more answers

2.26-30 3x+y=6 (0,_) (_,0) (3,_) (6,_) (5,_)

bekas [8.4K]

Answer:

Step-by-step explanation:

In ordered pairs (a,b) a is the x value and b is a y value.

if we have 3x+y=6

if x=0, y=6 --> (0,6)

if y=0, x=2 -->(2,0)

if x=3, y=-3--> (3, -3)

if x=6, y= -12 --->(6, -12)

if x=6, y= -9 ---> (5, -9)

7 0

2 years ago

A mass weighing 3 lb stretches a spring 3 in. If the mass is pushed upward, contracting the spring a distance of 1 in and then s

Bas_tet [7]

Answer:

Step-by-step explanation:

$m=\frac{3}{32}\\ \gamma =0\text{ damping constant.}\\ k=\frac{3}{\frac{1}{4}}=12\\ F(t)=0\\ \text{so equation of motion is }\\ mu''+\gamma u'+ku=F(t)\\ \frac{3u''}{32}+12u=0\\ u''+128u=0\\ \text{and initial conditions are}\\ u(0)=-\frac{1}{12}\\ u'(0)=2\\ u''+128u=0\\ \text{characterstic equation is}\\ r^2+128=0\\ \text{roots are }\\ r=\pm 8\sqrt{2}i\\ \text{therefore general solution is}\\ u(t)=A\cos8\sqrt{2}t+Bsin8\sqrt{2}t\\ \text{using initial conditions we get}\\ A=-\frac{1}{12}\\ B=\frac{\sqrt{2}}{8}\\ \text{therefore solution is }\\ u(t)=-\frac{1}{12}\cos8\sqrt{2}t+\frac{\sqrt{2}}{8}\sin8\sqrt{2}t\\
{hence}\\R=\sqrt{\frac{11}{288}}\\\\\sigma=\pi - \tan^{-1}\frac{1}{\sqrt{2}}\\\\\omega_0=8\sqrt{2}\\T=\frac{4}{4\sqrt{2}}$

3 0

3 years ago