How to solve partical quotients 7435÷5

Mathematics

2 answers:

Firlakuza [10]3 years ago

8 0

The answer to this problem is 1487

Simora [160]3 years ago

5 0

7435 divided by 5 equals 1487

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Find the length of the curve y = integral from 1 to x of sqrt(t^3-1)

Arlecino [84]

$y=\displaystyle\int_1^x\sqrt{t^3-1}\,\mathrm dt$

By the fundamental theorem of calculus,

$\dfrac{\mathrm dy}{\mathrm dx}=\dfrac{\mathrm d}{\mathrm dx}\displaystyle\int_1^x\sqrt{t^3-1}\,\mathrm dt=\sqrt{x^3-1}$

Now the arc length over an arbitrary interval $(a,b)$ is

$\displaystyle\int_a^b\sqrt{1+\left(\frac{\mathrm dy}{\mathrm dx}\right)^2}\,\mathrm dx=\int_a^b\sqrt{1+x^3-1}\,\mathrm dx=\int_a^bx^{3/2}\,\mathrm dx$

But before we compute the integral, first we need to make sure the integrand exists over it. $x^{3/2}$ is undefined if $x$ , so we assume $a\ge0$ and for convenience that $a$ . Then

$\displaystyle\int_a^bx^{3/2}\,\mathrm dx=\frac25x^{5/2}\bigg|_{x=a}^{x=b}=\frac25\left(b^{5/2}-a^{5/2}\right)$

6 0

3 years ago

Help me please!<br> If you get it right, I’ll will brainliest u!!

Hitman42 [59]

Answer:

A :)

Step-by-step explanation:

Law of Syllogism: q=r r=q

If complementary angles = 90-degree angles, then 90-degree angles = complementary angles

3 0

3 years ago

I need help with this two questions.

mezya [45]

Always get rid of denominators first. Multiply both right and left side by 6
-7 (6) = -c (6)/6 + 12(6)
-42 = -c + 72
c = 72 +42
c = 114

rearrange like terms together
42 = 18 - 4x
4x = 18 -42
4x = -24
divide both sides by 4
x = -6

8 0

3 years ago

(3 × 1,000) + (4 × 100) + (5 × 10) + (2 × 1)

aliina [53]

Answer:

3452

Step-by-step explanation:

Simplify the expression, and add/muiltiply where necessary.

4 0

1 year ago

Read 2 more answers

5 weeks = how many days???