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barxatty [35]
3 years ago
13

I am a quadrilateral with 2 pairs of opposite sides that are parallel, 2 pairs of sides that are of equal length,and 4 right ang

les. I am not a square. What shape am I?
Mathematics
1 answer:
Ludmilka [50]3 years ago
5 0

Answer:

Rectangle

Step-by-step explanation:

The shape is of a rectangle who has got two pairs of opposite sides that are parallel and two pairs of sides that are of equal length of each other with all  the four right angles that makes up total angle of 360 degrees in total. It can be acquired that the area which is equal to length multiply by breadth.

Calculation,

A length of the rectangle is equal to each other,

Assuming it to be 3cm,

Breadth of it is equal to each other,

Assuming that to be 2cm,

Length x Breadth = Area

3 x 2 = 6cm to the power 2.

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lesantik [10]
9.09% increase.

First find the difference between the two numbers.

(4)

then, divide the result by the original amount...

4÷ 44

then multiply by 100

9.09 and that is to the nearest 10th otherwise your answer 9% increase from 44 to 48.
3 0
3 years ago
Sari is teaching her best friend how to factor trinomials with a leading coefficient greater than 1. She starts with the trinomi
Eva8 [605]

Answer:

See explanation

2x^2+5x+3=(x+1)(2x+3)

Step-by-step explanation:

1. Make sure that the trinomial is written in the correct order - the trinomial must be written in descending order from highest power to lowest power. In you case, the trinomial must be written as

2x^2+5x+3

2. Decide if the three terms have anything in common, called the greatest common factor or GCF. If so, factor out the GCF. Do not forget to include the GCF as part of your final answer.

In your case, coefficients 2, 5 and 3 do not have common factors, so go to the next step.

3. Multiply the leading coefficient and the constant, that is multiply the first and last numbers together:

2\cdot 3=6

4. List all of the factors from step 3 and decide which combination of numbers will combine to get the number next to x:

6=1\cdot 6\\ \\ \bf{6=2\cdot 3}

5. After choosing the correct pair of numbers, you must give each number a sign so that when they are combined they will equal the number next to x and also multiply to equal the number found in Step 3:

2+3=5

6. Rewrite the original problem with four terms by splitting the middle term into the two numbers chosen in step 5:

2x^2+5x+3=2x^2+2x+3x+3

7. Now that the problem is written with four terms, you can factor by grouping:

2x^2 +2x+3x+3=(2x^2+2x)+(3x+3)=2x(x+1)+3(x+1)=(x+1)(2x+3)

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Answer:

Step-by-step explanation:

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3 years ago
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A rectangular table is 22.5 inches wide and 31 inches long using the Pythagorean theorem what is the length of the diagonal of t
Stolb23 [73]
38
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3 years ago
1. (a) Solve the differential equation (x + 1)Dy/dx= xy, = given that y = 2 when x = 0. (b) Find the area between the two curves
erastova [34]

(a) The differential equation is separable, so we separate the variables and integrate:

(x+1)\dfrac{dy}{dx} = xy \implies \dfrac{dy}y = \dfrac x{x+1} \, dx = \left(1-\dfrac1{x+1}\right) \, dx

\displaystyle \frac{dy}y = \int \left(1-\frac1{x+1}\right) \, dx

\ln|y| = x - \ln|x+1| + C

When x = 0, we have y = 2, so we solve for the constant C :

\ln|2| = 0 - \ln|0 + 1| + C \implies C = \ln(2)

Then the particular solution to the DE is

\ln|y| = x - \ln|x+1| + \ln(2)

We can go on to solve explicitly for y in terms of x :

e^{\ln|y|} = e^{x - \ln|x+1| + \ln(2)} \implies \boxed{y = \dfrac{2e^x}{x+1}}

(b) The curves y = x² and y = 2x - x² intersect for

x^2 = 2x - x^2 \implies 2x^2 - 2x = 2x (x - 1) = 0 \implies x = 0 \text{ or } x = 1

and the bounded region is the set

\left\{(x,y) ~:~ 0 \le x \le 1 \text{ and } x^2 \le y \le 2x - x^2\right\}

The area of this region is

\displaystyle \int_0^1 ((2x-x^2)-x^2) \, dx = 2 \int_0^1 (x-x^2) \, dx = 2 \left(\frac{x^2}2 - \frac{x^3}3\right)\bigg|_0^1 = 2\left(\frac12 - \frac13\right) = \boxed{\frac13}

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3 years ago
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